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Harman [31]
2 years ago
15

What value of m makes the statement true? –(m + 15) = –18 + (–15) A. –33 B. –18 C. 3 D. 18

Mathematics
2 answers:
hram777 [196]2 years ago
3 0
B. -18 

you have to distribute 


yarga [219]2 years ago
3 0
B-18 because you have to solve the equation with every answer choice.
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The equation h=7sin(pi/21t)+28 can be used to model the height, h, in feet of the end of one blade of a windmill turning on an a
satela [25.4K]

Answer:

7 feet is the length of the blade of the windmill.

Step-by-step explanation:

We have the equation

h = 7 sin(pi/21t) + 28 ------ eq1

At time 't' = 0, the end of the blade is pointing to the right parallel to the ground meaning it is at the same height as the other end. (Ф = 0°)

So, by calculating the maximum height of this end at  Ф = 90°. we can calculate the length of the blade.

Now, we know that a general model equation of a circular simple harmonic motion is represented as :     y = A sinωt + k ----- eq2

Where A is the amplitude that is, maximum displacement from mean to maximum position.

ω is the angular frequency.

Comparing eq1 and eq2:

A = 7

so the difference in blades end height at Ф = 0° and Ф = 90° is 7 feet.

Hence, the length of the blade is 7 feet.

4 0
3 years ago
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Can you guys help me with this question
VLD [36.1K]

Answer:

2+2=4 quick mafs

Step-by-step explanation:

3 0
3 years ago
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What is the value of x
Afina-wow [57]

Answer:

4

Step-by-step explanation:

Sin(30) = LJ/8sqrt(3)

Sin 30 = ½

LJ = 4sqrt(2)

LM = JM = x

x² + x² = (4sqrt(2))²

2x² = 32

x² = 16

x = 4

6 0
3 years ago
Find the exact value of tan (arcsin (two fifths)). For full credit, explain your reasoning.
Hitman42 [59]
\bf sin^{-1}(some\ value)=\theta \impliedby \textit{this simply means}
\\\\\\
sin(\theta )=some\ value\qquad \textit{now, also bear in mind that}
\\\\\\
sin(\theta)=\cfrac{opposite}{hypotenuse}\qquad 
\qquad 
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}\\\\
-------------------------------\\\\

\bf sin^{-1}\left( \frac{2}{5} \right)=\theta \impliedby \textit{this simply means that}
\\\\\\
sin(\theta )=\cfrac{2}{5}\cfrac{\leftarrow opposite}{\leftarrow hypotenuse}\qquad \textit{now let's find the adjacent side}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}

\bf \pm \sqrt{5^2-2^2}=a\implies \pm\sqrt{21}=a
\\\\\\
\textit{we don't know if it's +/-, so we'll assume is the + one}\quad \sqrt{21}=a\\\\
-------------------------------\\\\
tan(\theta)=\cfrac{opposite}{adjacent}\qquad \qquad tan(\theta)=\cfrac{2}{\sqrt{21}}
\\\\\\
\textit{and now, let's rationalize the denominator}
\\\\\\
\cfrac{2}{\sqrt{21}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies \cfrac{2\sqrt{21}}{(\sqrt{21})^2}\implies \cfrac{2\sqrt{21}}{21}

7 0
3 years ago
Estimate the sum 7 8/9 + 3.1
Yanka [14]

Answer:

\large\boxed{7\dfrac{8}{9}+3.1=10\dfrac{89}{90}}

Step-by-step explanation:

\text{Convert the decimal to the fraction:}\\\\3.1=\dfrac{31}{10}=3\dfrac{1}{10}\\\\7\dfrac{8}{9}+3.1=7\dfrac{8}{9}+3\dfrac{1}{10}\\\\\text{The common denominator is 90.}\\90=9\cdot10\\\\7\dfrac{8}{9}=7\dfrac{8\cdot10}{9\cdot10}=7\dfrac{80}{90}\\\\3\dfrac{1}{10}=3\dfrac{1\cdot9}{10\cdot9}=3\dfrac{9}{90}\\\\\\7\dfrac{8}{9}+3.1=7\dfrac{80}{90}+3\dfrac{9}{90}=(7+3)+\dfrac{80+9}{90}=10\dfrac{89}{90}

3 0
3 years ago
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