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eimsori [14]
3 years ago
12

A wire is first bent into the shape of a triangle. Each side of the triangle is 16 long. Then the wire is unbent and reshaped in

to a rectangle. If the length of the rectangle is 15 in, what is its width?
Mathematics
1 answer:
34kurt3 years ago
5 0

Answer:

the width is 9in

Step-by-step explanation:

perimeter of triangle =3×16 = 48

let w= width of rectangle

perimeter of triangle = perimeter of rectangle

48= 2(15 +w)

24= 15 + w

w= 9

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41 ÷ 1

15 ÷ 1

Reduced fraction:

41

15

Therefore, 41/15 simplified to lowest terms is 41/15.

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3 years ago
The width of a rectanle is 8n - 8.5 feet and the lenght is 8.5n + 10 feet. Find the perimeter of the rectangle
Wittaler [7]

Answer:

The perimeter of a rectangle is:

  • P = 33n+3

Step-by-step explanation:

Given

The width of a rectangle w =  8n - 8.5 feet

The length of a rectangle l = 8.5n + 10 feet

To determine

The perimeter of a rectangle = P = ?

The perimeter of a rectangle can be determined using the formula

P = 2(l+w)

substitute l = 8.5n + 10 and w = 8n - 8.5

P=2\left(8.5n+10+8n-8.5\right)

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   =33n+3

Therefore, the perimeter of a rectangle is:

  • P = 33n+3
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