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zubka84 [21]
3 years ago
11

· A dead tree in the forest is decaying at a rate of 14% per year. If the tree weighs 1500 lbs

Mathematics
1 answer:
guapka [62]3 years ago
3 0
The exact answer would be 4.285714 years but if you rounded it would be 4.3 years
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Max Play´s his games for 20 min an he started at 9:00
skelet666 [1.2K]

Answer:

so 9:20

Step-by-step explanation:

I'm confused by this question

8 0
3 years ago
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In response to a gss question in 2006 about the number of hours spent per day watching television, the responses by the fifteen
NemiM [27]

Answer:

Standard error = 0.4

Step-by-step explanation:

Step 1

We find the Standard Deviation

The formula = √(x - mean)/n - 1

n = 15

Mean = 1.93 hours

= √(0- 1.93)² + (0-1.93)² +(0- 1.93)²+( 0- 1.93)²+ (1- 1.93)² + (1- 1.93)² +(1 - 1.93)² +(2 - 1.93)² + (2 - 1.93)² + (2 - 1.93)² + (2 - 1.93)² + ( 2 - 1.93)² +(4 - 1.93)² +(4 - 1.93)² + (5 - 1.93)²/15 - 1

= √(3.737777776 + 3.737777776 + 3.737777776 + 0.871111111 +0.871111111 + 0.871111111 + 0.004444444445+ 0.004444444445 + 0.004444444445 + 0.004444444445 + 0.004444444445 + 1.137777778 + 4.271111112 + 4.271111112 + 9.404444446)/15 - 1

= √2.352380952

= 1.533747356

Step 2

We find the standard error

The formula = Standard Deviation/√n

Standard deviation = 1.533747356

n = 15

= 1.533747356/√15

= 1.533747356 /3.87298334621

= 0.39601186447

Approximately = 0.4

Therefore, the standard error is 0.4

4 0
3 years ago
BEING TIMED !! <br> In circle O, the length of arc AB is 2(pi) and the radius is 5. Find the
inn [45]

Answer:

31.4

Step-by-step explanation:

3.14 x 2 x 5 = 31.4

8 0
3 years ago
Can someone please help me with the second question….will give brainliest :(
Andrej [43]

Answer:

2

Step-by-step explanation:

7 0
3 years ago
You play two games against the same opponent. The probability you win the first game is 0.4. If you win the first game, the prob
Ilia_Sergeevich [38]

Answer:

a) No

b) 42%

c) 8%

d) X               0                 1                2

   P(X)           42%            50%         8%

e) 0.62

Step-by-step explanation:

a) No, the two games are not independent because the the probability you win the second game is dependent on the probability that you win or lose the second game.

b) P(lose first game) = 1 - P(win first game) = 1 - 0.4 = 0.6

P(lose second game) = 1 - P(win second game) = 1 - 0.3 = 0.7

P(lose both games) = P(lose first game)  × P(lose second game) = 0.6 × 0.7 = 0.42 = 42%

c)   P(win first game)  = 0.4

P(win second game) = 0.2

P(win both games) = P(win first game)  × P(win second game) = 0.4 × 0.2 = 0.08 = 8%

d) X               0                 1                2

   P(X)           42%            50%         8%

P(X = 0)  =  P(lose both games) = P(lose first game)  × P(lose second game) = 0.6 × 0.7 = 0.42 = 42%

P(X = 1) = [ P(lose first game)  × P(win second game)] + [ P(win first game)  × P(lose second game)] = ( 0.6 × 0.3) + (0.4 × 0.8) = 0.18 + 0.32 = 0.5 = 50%

e) The expected value  \mu=\Sigma}xP(x)= (0*0.42)+(1*0.5)+(2*0.08)=0.66

f) Variance \sigma^2=\Sigma(x-\mu^2)p(x)= (0-0.66)^2*0.42+ (1-0.66)^2*0.5+ (2-0.66)^2*0.08=0.3844

Standard deviation \sigma=\sqrt{variance} = \sqrt{0.3844}=0.62

8 0
3 years ago
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