Supposse that the distance from the point 
to the point 
is equal to the distance from to the point 
. Then, by the formula of the distnace we must have
cancel the square root and the 
's, and then expand the parenthesis to obtain
then, simplifying we obtain
therfore we must have
this means that the points satisfying the propertie must have first component equal to 5. So we can give a lot of examples of such points: 
. The set of this points give us a straight line and the points (3,0) and (7,0) are symmetric with respect to this line.
Answer:11
Step-by-step explanation: Bases of trapezoid : 11 meters and 14 meters
height of trapezoid : 10 meters
Area of trapezoid = (sum of bases / 2) height
A = (11m + 14m)/2 * 10m
A = 25m / 2 * 10m
A = 12.5m * 10m
A = 125m²
Answer:
median: 10 <h <13
mean: 12.12
Step-by-step explanation:
Answer:
$4.80
Step-by-step explanation:
Make a proportion
$12 for 2.5 pounds, and $x for 1 pound
12/2.5=x/1
x/1 is equivalent to x
12/2.5=x
Divide
x=4.8
So, one pound of peanuts costs $4.80
<span>Find the exact value of sec(-4π/3). Note that one full rotation, clockwise, would be -2pi. We have to determine the Quadrant in which this angle -4pi/3 lies. Think of this as 4(-pi/3), or 4(-60 degrees). Starting at the positive x-axis and rotating clockwise, we reach -60, -120, -180 and -240 degrees. This is in Q III. The ray representing -240 has adj side = -1 and opp side = to sqrt(3).
Using the Pyth. Theorem to find the length of the hypo, we get hyp = 2.
Thus, the secant of this angle in QIII is hyp / adj, or 2 / sqrt(3) (answer). This could also be written as (2/3)sqrt(3).
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