You can set up an equation of a line where it has a slope-intercept form written as y=mx + b where m is the slope and b is the y-intercept. The slope is calculated by the change in y over the change in x. Hope this answers the question. Have a nice day
Answer:
See description.
Step-by-step explanation:
Any graph where the two lines intersect at (-3/2, 0) will be the correct graph.
Here is an attached example.
Answer:
86.7 ft²
Step-by-step explanation:
arc area = area of the circle x ( arc angle measure / 360°)
area of the circle = 65 / (270/360) = 86.67 ft²
Answer:
Step-by-step explanation:
Nothing in the problem statement tells you anything about the directions of lines LK or QT, so you cannot conclude they are parallel. You only know that EV crosses CN and KT at right angles.
EJ ⊥ CN means m∠CJV = 90°, as all angles at the intersection of EJ and CN are 90°.
