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muminat
3 years ago
7

Use determinants to find out if the matrix is invertible.[Start 3 By 3 Matrix 1st Row 1st Column 20 2nd Column 5 3rd Column 3 2n

d Row 1st Column 4 2nd Column negative 15 3rd Column 6 3rd Row 1st Column 0 2nd Column 25 3rd Column negative 9 EndMatrix ]The determinant of the matrix is180180. ​(Simplify your​ answer.)Is the matrix​ invertible? Choose the correct answer below.A.The matrix is not invertible because the determinant is defined.B.The matrix is invertible because the determinant is defined.C.The matrix is not invertible because the determinant is not zero.
Mathematics
1 answer:
yawa3891 [41]3 years ago
7 0

Answer:

B.The matrix is invertible because the determinant is defined.

Step-by-step explanation:

<u>Definition:</u> A matrix is invertible if the determinant is not equal to zero.

Given the matrix:

A=\left(\begin{array}{ccc}20&5&3\\4&-15&6\\0&25&-9\end{array}\right)

The determinant of the matrix:

|A|=20\left|\begin{array}{ccc}-15&6\\25&-9\end{array}\right|-5\left|\begin{array}{ccc}4&6\\0&-9\end{array}\right|+3\left|\begin{array}{ccc}4&-15\\0&25\end{array}\right|

|A|=20(-15*-9-25*6)-5(-9*4-6*0)+3(4*25-0*-15)\\=20(135-150)-5(-36-0)+3(100+0)\\=20(-15)-5(-36)+3(100)\\=-300+180+300\\|A|=180

Since the determinant, |A|\neq 0, the matrix is invertible because the determinant is defined.

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O.6 as a mixed number
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Answer:

3/5

Step-by-step explanation:

To make 0.6 as a fraction (you can't make it a mixed number because there is no number to the left of the point) place a 1 under it to make it a fraction:

0.6/1

Since you can't have a decimal on a fraction, multiply by 10;

0.6/1 × 10/10 =6/10

Simply your answer (6/10) to get 3/5

6 0
3 years ago
Can anyone figure this out for me please? It would be greatly appreciated.
Ira Lisetskai [31]
Check the picture below.

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8 0
3 years ago
Software to detect fraud in consumer phone cards tracks the number of metropolitan areas where calls originate each day. It is f
pashok25 [27]

Answer:

0.999987

Step-by-step explanation:

Given that

The user is a legitimate one = E₁

The user is a fraudulent one = E₂

The same user originates calls from two metropolitan areas  = A

Use Bay's Theorem to solve the problem

P(E₁) = 0.0131% = 0.000131

P(E₂) = 1 - P(E₁)  = 0.999869

P(A/E₁) = 3%  = 0.03

P(A/E₂) = 30% = 0.3

Given a randomly chosen user originates calls from two or more metropolitan, The probability that the user is fraudulent user is :

P(E_2/A)=\frac{P(E_2)\times P(A/E_2)}{P(E_1)\times P(A/E_1)+P(E_2)\times P(A/E_2)}

=\frac{(0.999869)(0.3)}{(0.000131)(0.03)+(0.999869)(0.3)}

\frac{0.2999607}{0.00000393+0.2999607}

\frac{0.2999607}{0.29996463}

= 0.999986898 ≈ 0.999987

6 0
3 years ago
What is 2<img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%7D" id="TexFormula1" title="\frac{1}{5}" alt="\frac{1}{5}" align="
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7 0
3 years ago
Please Help:
dolphi86 [110]
I would maybe say a Rhombus. They have two likes of symmetry ^^ Hope this helps!
4 0
3 years ago
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