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muminat
3 years ago
7

Use determinants to find out if the matrix is invertible.[Start 3 By 3 Matrix 1st Row 1st Column 20 2nd Column 5 3rd Column 3 2n

d Row 1st Column 4 2nd Column negative 15 3rd Column 6 3rd Row 1st Column 0 2nd Column 25 3rd Column negative 9 EndMatrix ]The determinant of the matrix is180180. ​(Simplify your​ answer.)Is the matrix​ invertible? Choose the correct answer below.A.The matrix is not invertible because the determinant is defined.B.The matrix is invertible because the determinant is defined.C.The matrix is not invertible because the determinant is not zero.
Mathematics
1 answer:
yawa3891 [41]3 years ago
7 0

Answer:

B.The matrix is invertible because the determinant is defined.

Step-by-step explanation:

<u>Definition:</u> A matrix is invertible if the determinant is not equal to zero.

Given the matrix:

A=\left(\begin{array}{ccc}20&5&3\\4&-15&6\\0&25&-9\end{array}\right)

The determinant of the matrix:

|A|=20\left|\begin{array}{ccc}-15&6\\25&-9\end{array}\right|-5\left|\begin{array}{ccc}4&6\\0&-9\end{array}\right|+3\left|\begin{array}{ccc}4&-15\\0&25\end{array}\right|

|A|=20(-15*-9-25*6)-5(-9*4-6*0)+3(4*25-0*-15)\\=20(135-150)-5(-36-0)+3(100+0)\\=20(-15)-5(-36)+3(100)\\=-300+180+300\\|A|=180

Since the determinant, |A|\neq 0, the matrix is invertible because the determinant is defined.

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Now we know that, probability of an event E is

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So here number of outcomes for spinning a 3 is 1 and we have got total outcomes = 8.

So P(Three) = \frac{1}{8}

Similarly, P(Eight) = \frac{1}{8}

Probability of spinning a 3 or an 8 = P(Three) + P(Eight)

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As the denominator is same we can add the numerator.

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Now we have to simplify the fraction by dividing the numerator and denominator by a common factor of them.

The common factor of 2 and 8 is 2. So by dividing them we will get,

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We have got the required answer.

The probability of spinning a 3 or an 8 is \frac{1}{4}


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3 years ago
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