All categories

3 years ago

Use the diagram. AB is a diameter, and AB is perpendicular to CD. The figure is not drawn to scale.

Mathematics

1 answer:

Stells [14]3 years ago

4 0

Answer:

i) mAB = mBD (Not True)

Step-by-step explanation:

ii) mAC = mAD , CD is a chord and AB is a diameter. CD⊥AB and hence AC = AD,

Equal chords have equal segments . Hence it is true

iii) ∠BDA = ∠BCA true

iv) ∠PBC = ∠DBA True

Hence the three options are correct except the one.

So our answer is option A mAB = mBD (Not True)

You might be interested in

Which of the following is the solution to the following system of inequalities?

seropon [69]

It is 30 bc u dived then subtract

5 0

3 years ago

Show that ( 2xy4 + 1/ (x + y2) ) dx + ( 4x2 y3 + 2y/ (x + y2) ) dy = 0 is exact, and find the solution. Find c if y(1) = 2.

fredd [130]

$\dfrac{\partial\left(2xy^4+\frac1{x+y^2}\right)}{\partial y}=8xy^3-\dfrac{2y}{(x+y^2)^2}$

$\dfrac{\partial\left(4x^2y^3+\frac{2y}{x+y^2}\right)}{\partial x}=8xy^3-\dfrac{2y}{(x+y^2)^2}$

so the ODE is indeed exact and there is a solution of the form $F(x,y)=C$ . We have

$\dfrac{\partial F}{\partial x}=2xy^4+\dfrac1{x+y^2}\implies F(x,y)=x^2y^4+\ln(x+y^2)+f(y)$

$\dfrac{\partial F}{\partial y}=4x^2y^3+\dfrac{2y}{x+y^2}=4x^2y^3+\dfrac{2y}{x+y^2}+f'(y)$

$f'(y)=0\implies f(y)=C$

$\implies F(x,y)=x^2y^3+\ln(x+y^2)=C$

With $y(1)=2$ , we have

$8+\ln9=C$

$\boxed{x^2y^3+\ln(x+y^2)=8+\ln9}$

8 0

3 years ago

Jessica walks 12 miles in 3hrs. How many miles does she walk in one hour

ehidna [41]

3 hours = 12 miles

1 hour = 12 ÷ 3 = 4 miles

Answer: 4 miles

5 0

4 years ago

Use a graphing calculator to sketch the graph of the quadratic equation, and then state the domain and range. y=x^2+x+9 a. D: al

taurus [48]

Answer: Option c. D: all real numbers R: (y ≥ 8.75)

Solution:

y=x^2+x+9

Domain: all real numbers = ( - Infinite, Infinite)

y=ax^2+bx+c

a=1 > 0, the parabola opens upward: Range: y ≥k

b=1

c=9

Vertex: V=(h,k)

h=-b/(2a)

h=-1/(2(1))

h=-1/2

h=-0.5

k=y=h^2+h+9

k=(-0.5)^2+(-0.5)+9

k=0.25-0.5+9

k=8.75

Range: y≥k

Range: y≥8.75

3 0

3 years ago

Read 2 more answers

18. The record low temperature in Fargo, ND is

Harman [31]

Answer:

149 F

Step-by-step explanation:

If you take -35 and find the absoulte value you get 35 and then add that too 114 you get 149.

8 0

3 years ago