x+(-2) >3
open the bracket
x-2>3
collect the like terms by taking 2 to the other side
x>3+2
x>6
Expanding the limit, we get (x^2+2x∆x+∆x^2-2x-2∆x+1-x^2+2x-1)/<span>∆x
Crossing the 1s , the 2xs, and the x^2s out, we get
(2x</span>∆x+∆x^2-2∆x)/<span>∆x
Dividing the </span><span>∆x, we get
2x+</span><span>∆x-2.
Making the limit of </span><span>∆x=0, we get 2x-2.</span>
Answer:
(2,4)
Step-by-step explanation:
look at the x axis and y axis and see where they meet
Answer:
18.00 dollars
Step-by-step explanation:
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