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3 years ago

Solve for f 2f = -12f=?

Mathematics

1 answer:

Nookie1986 [14]3 years ago

3 0

Answer:

f = -6

Step-by-step explanation:

2 it's multiplying the f, so in order to get only f, you need to divide both sides by 2

2f / 2 = -12 / 2

f = -6

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Suppose that the division N/5 leaves a remainder of 4, and the division N/2 leaves a remainder of 1, what is the ones digit on N

Tju [1.3M]

Since N/2 leaves a remainder, N must be odd and ends with 1, 3, 5, 7, or 9.

N/5 also leaves a remainder, so N is not divisible by 5, so it does not end in 5.

The only correct choice is then 9, since

1 = 0•5 + 1 and 1 = 0•2 + 1

3 = 0•5 + 3 and 3 = 1•2 + 1

7 = 1•5 + 2 and 7 = 3•2 + 1

9 = 1•5 + 4 and 9 = 4•2 + 1

Alternatively, the given information is equivalent to saying

$N\equiv 4\pmod5\\\\N\equiv1\pmod2$

Then you can use the Chinese remainder theorem to find N.

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3 years ago

The volume of a sphere can be determined by the formula V = 4/3 πr^3, where r is the radius. What is the volume of a sphere with

allochka39001 [22]

Answer:

$V = \frac{99}{7} x^{9}y^{-6}$

Step-by-step explanation:

Given

$V = \frac{4}{3}\pi r^3$

Required

Find V when

$r = \frac{3}{2}x^3y^{-2$

Substitute $\frac{3}{2}x^3y^{-2$ for r in $V = \frac{4}{3}\pi r^3$

$V = \frac{4}{3}\pi * (\frac{3}{2}x^3y^{-2})^3$

Open bracket

$V = \frac{4}{3}\pi * \frac{3}{2}^3 * x^{3*3}y^{-2*3}$

$V = \frac{4}{3}\pi * \frac{27}{8} * x^{9}y^{-6}$

Simplify the fractions

$V = \pi * \frac{9}{2} * x^{9}y^{-6}$

Let

$\pi = \frac{22}{7}$

So:

$V = \frac{22}{7} * \frac{9}{2} * x^{9}y^{-6}$

$V = \frac{11}{7} * \frac{9}{1} * x^{9}y^{-6}$

$V = \frac{99}{7} * x^{9}y^{-6}$

$V = \frac{99}{7} x^{9}y^{-6}$

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3 years ago

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Answer:

Step-by-step explanation:

i believe the answer is 7.33333333333 feet per second

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Bad White [126]

Answer: 35

Step-by-step explanation:

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Answer:

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