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ryzh [129]
3 years ago
11

Mica and Denise are reading the same novel. Mica has read 1/2 of the novel,Denise has read 1/3 of the novel . How much more of t

he novel has mica read than denis? Needs help with my homework!!

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
5 0
The answer would be 1/6 more.
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A container is filled with blueberries. 1/6 of the blueberries are poured equally into two bowls. What fraction of the blueberri
andrew11 [14]
Well as 1/6 is already being taken away as it is being split again multiply the 6 by 2 so 1/12 of the blueberries are in each bowel
7 0
3 years ago
For which value of θ is tan θ equal to sin θ?
UkoKoshka [18]

Answer:

Step-by-step explanation:

tan \theta=sin \theta\\tan~ \theta-sin~ \theta=0\\\frac{sin ~\theta}{cos~\theta} -sin\theta=0\\multiply ~by~cos~\theta\\sin ~\theta-sin~\theta~cos~\theta=0\\sin \theta(1-cos \theta)=0\\sin~\theta=0=sin k\pi \theta=k \pi ,where~k~is~an~integer.\\or cos\theta=1=cos 2k\pi \\\theta=2k\pi \\where~k~ is~an ~integer.\\combining\\\theta=k\pi \\where~k~is~an~integer.

4 0
3 years ago
Please help out with this geometry homework I was assigned. And what formula do I use?
lozanna [386]

Answer:

V_{cone}   \approx 1,178.97 \:  {in}^{3}

Step-by-step explanation:

Diameter of cone = 16 in

Radius of cone r = 16/2 = 8 in

Height of cone h = 17.6 in

V_{cone}  =  \frac{1}{3} \pi {r}^{2}h \\  \\  V_{cone}  =  \frac{1}{3}  \times 3.14 \times  {(8)}^{2} \times 17.6 \\  \\   V_{cone}  =  \frac{1}{3}  \times 3,536.896 \\  \\  V_{cone}  =  1,178.96533 \\  \\  V_{cone}   \approx 1,178.97 \:  {in}^{3}  \\

5 0
3 years ago
The diagram shows how cos θ, sin θ, and tan θ relate to the unit circle. Copy the diagram and show how sec θ, csc θ, and cot θ r
DIA [1.3K]
<span>Copy the diagram and show how sec θ, csc θ, and cot θ relate to the unit circle. 

The representation of the diagram is shown if Figure 1. There's a relationship between </span>sec θ, csc θ, and cot θ related the unit circle. Lines green, blue and pink show the relationship. 

a.1 First, find in the diagram a segment whose length is sec θ. 

The segment whose length is sec θ is shown in Figure 2, this length is the segment \overline{OF}, that is, the line in green.

a.2 <span>Explain why its length is sec θ.

We know these relationships:

(1) sin \theta=\frac{\overline{BD}}{\overline{OB}}=\frac{\overline{BD}}{r}=\frac{\overline{BD}}{1}=\overline{BD}

(2) </span>cos \theta=\frac{\overline{OD}}{\overline{OB}}=\frac{\overline{OD}}{r}=\frac{\overline{OD}}{1}=\overline{OD}
<span>
(3) </span>tan \theta=\frac{\overline{FD}}{\overline{OC}}=\frac{\overline{FC}}{r}=\frac{\overline{FC}}{1}=\overline{FC}
<span>
Triangles </span>ΔOFC and ΔOBD are similar, so it is true that:

\frac{\overline{FC}}{\overline{OF}}= \frac{\overline{BD}}{\overline{OB}}<span>

</span>∴ \overline{OF}= \frac{\overline{FC}}{\overline{BD}}= \frac{tan \theta}{sin \theta}= \frac{1}{cos \theta} \rightarrow \boxed{sec \theta= \frac{1}{cos \theta}}<span>

b.1 </span>Next, find cot θ

The segment whose length is cot θ is shown in Figure 3, this length is the segment \overline{AR}, that is, the line in pink.

b.2 <span>Use the representation of tangent as a clue for what to show for cotangent. 
</span>
It's true that:

\frac{\overline{OS}}{\overline{OC}}= \frac{\overline{SR}}{\overline{FC}}

But:

\overline{SR}=\overline{OA}
\overline{OS}=\overline{AR}

Then:

\overline{AR}= \frac{1}{\overline{FC}}= \frac{1}{tan\theta} \rightarrow \boxed{cot \theta= \frac{1}{tan \theta}}

b.3  Justify your claim for cot θ.

As shown in Figure 3, θ is an internal angle and ∠A = 90°, therefore ΔOAR is a right angle, so it is true that:

cot \theta= \frac{\overline{AR}}{\overline{OA}}=\frac{\overline{AR}}{r}=\frac{\overline{AR}}{1} \rightarrow \boxed{cot \theta=\overline{AR}}

c. find csc θ in your diagram.

The segment whose length is csc θ is shown in Figure 4, this length is the segment \overline{OR}, that is, the line in green.

3 0
4 years ago
If g(x) = -25, then x =
statuscvo [17]
Answer :

-25

!!!!!!!!!!!!!!!!!
5 0
3 years ago
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