Given:
Principal = Rs. 1200
Rate of interest = 25%
To find:
The time in which the interest will became equal to the principal.
Solution:
We have,
If interest is equal to the principal, then
The formula for amount is:
Substituting 
in the above formula, we get
Taking log on both sides, we get
![[\because \log a^b=b\log a]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog%20a%5Eb%3Db%5Clog%20a%5D)
Therefore, the interest will became equal to the principal in about 3.11 years.
10^13 cause you add the exponents together
"<span>A company will need 40,000 in 6 years for a new addition. To meet the goal, the company deposits money into an account today that pays 4% annual intrest compund quarterly." Let's pretend that the instructions state, "Determine the amount of money that must be deposited upfront so that you will have $40,000 in 6 years."
Use the Compound Amount formula: A = P(1 + r/n)^(nt),
where P is the principal (the amount deposited upfront), r is the interest rate as a decimal fraction, n is the number of compounding periods, and t is the time in years.
Here, $40000 = P(1 + 0.04/4)^(4*6)
$40000
So the upfront $ needed is P = -------------------------
(1+0.01)^24
This comes out to $31502.65 (answer)</span>
The answer is 8
hopefully that helps you
Here, Your Original expression is 60x - 24.
Take 12 as common, which is GCD of 24 & 60,
Therefore, It would be:
60x - 24
= 12 * 5x - 12 * 2
= 12 (5x - 2)
In short, your Answer would be 12(5x - 2)
Hope this helps!
Photon
