Substation method x-2y=5 , 3x-5y=8

1 answer:

6 0

$x-2y=5 \\
3x-5y=8 \\ \\
\hbox{solve the first equation for x:} \\
x-2y=5 \ \ \ |+2y \\
x=2y+5 \\ \\
\hbox{substitute 2y+5 for x in the second equation:} \\
3(2y+5)-5y=8 \\
6y+15-5y=8 \\
y+15=8 \ \ \ |-15 \\
y=-7 \\ \\
x=2y+5=2 \times (-7)+5=-14+5=-9 \\ \\
\boxed{(x,y)=(-9,-7)}$

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2(5m^4n^-1)^3 simplify show work please

dangina [55]

Answer:

$\large\boxed{2(5m^4n^{-1})^3=250m^{12}n^{-3}=\dfrac{250m^{12}}{n^3}}$

Step-by-step explanation:

$\text{Use}\\\\(ab)^n=a^nb^n\\\\(a^n)^m=a^{nm}\\\\a^{-n}=\dfrac{1}{a^n}\\-------------------\\\\2(5m^4n^{-1})^3=2(5)^3(m^4)^3(n^{-1})^3=2(125)m^{3\cdot4}n^{-1\cdot3}=250m^{12}n^{-3}=\dfrac{250m^{12}}{n^3}$