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2 years ago

Look below giving brainliest plz dont answer it incorrect

Mathematics

2 answers:

USPshnik [31]2 years ago

6 0

1 is D 10,8

2 is B 10, 3

dmitriy555 [2]2 years ago

6 0

1) (10,8)

2) (10,3)

Do you want me to explain how I got it?

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What is the missing reason in the proof?

Nookie1986 [14]

A) corresponding angle theorem

3 0

3 years ago

Which value of x is in the domain of f(t) = squared x - 7

zloy xaker [14]

Given:

The given function is:

$f(x)=\sqrt{x-7}$

To find:

The value of x that is in the domain.

Solution:

Domain is the set of input values.

We have,

$f(x)=\sqrt{x-7}$

We know that the square root is defined for non negative values. So,

$x-7\geq 0$

$x\geq 0+7$

$x\geq 7$

Thus, the domain of the given function is all real number that are greater than or equal to 7.

In the given options 0, -3, 6 are less than 7 but 8 in option A is the only value that is greater than 7. So, $x=8$ is in the domain of the given function.

Therefore, the correct option is A.

8 0

2 years ago

Triangle ABC is similar to triangle PQR, as shown below:

natita [175]

Answer:

$\frac{q}{b}=\frac{r}{c}$

Step-by-step explanation:

Consider the options for this question are as follow,

$\frac{q}{c}=\frac{r}{b}$

$\frac{c}{p}=\frac{b}{a}$

$\frac{c}{a}=\frac{q}{r}$

$\frac{q}{b}=\frac{r}{c}$

Here, In triangles ABC and PQR,

AB = c, BC = a, AC = b, PQ = r, QR = p and PR = q,

Since,

$\traingle ABC\sim \triangle PQR$

We know that,

The corresponding sides of similar triangles are in same proportion,

Thus,

$\frac{AB}{PQ}=\frac{BC}{QR}=\frac{AC}{PR}$

$\frac{c}{r}=\frac{a}{p}=\frac{b}{q}$

$\frac{r}{c}=\frac{p}{a}=\frac{q}{b}$

$\implies \frac{q}{b}=\frac{r}{c}$

3 0

3 years ago

Read 2 more answers

gregori [183]

It’s D bc Dt= 15x3 and it’s not that hard to solve

6 0

3 years ago

The numbers of regular season wins for 10 football teams in a given season are given below. Determine the range, mean, variance,

galina1969 [7]

Answer:

Range = 13

Mean = 8.3

Variance = 17.61

Step-by-step explanation:

Given the population dataset :

2, 9, 15, 4, 12, 9, 13, 6, 3, 10

1.) Range : (maximum - minimum)

Maximum = 15 ; minimum = 2

Range = (15 - 2) = 13

2.) population mean (μ) :

μ = ΣX / n

n = sample size

μ = (2 + 9 + 15 + 4 + 12 + 9 + 13 + 6 + 3 + 10) / 10

μ = 83 / 10

μ = 8.3

3.) Population variance (s²)

Σ(x - μ)² / n

=[(2 - 8.3)^2 + (9 - 8.3)^2 + (15 - 8.3)^2 + (4 - 8.3)^2 + (12 - 8.3)^2 + (9 - 8.3)^2 + (13 - 8.3)^2 + (6 - 8.3)^2 + (3 - 8.3)^2 + (10 - 8.3)^2] / 10

s² = 176.1 / 10

s² = 17.61

8 0

3 years ago