Answer:
D. d = sqrt( ( x2-x1)^2 + (y2-y1)^2)
C. d = sqrt( ( x1-x2)^2 + (y1-y2)^2)
B. d = sqrt( (|x2-x1|^2 + |y2-y1|^2)
Step-by-step explanation:
Given two points (x1, y1) and (x2,y2) we can find the distance using
d = sqrt( ( x2-x1)^2 + (y2-y1)^2)
The order of the terms inside the square doesn't matter
d = sqrt( ( x1-x2)^2 + (y1-y2)^2)
When we are squaring are term, we can take the absolute value before we square and it does not change the value
d = sqrt( (|x2-x1|^2 + |y2-y1|^2)
487 + 310 ≈ 500 + 300 ≈ 800
F(t)
= t2 + 4t − 14
y + 14 + 4 = (
t2 + 4t +4)
y + 18 = ( t +
2)^2
so the vertex
of the parabola is ( -2 , -18)
<span>the axis of
symmetry is y = -18</span>
