Question

[I have no idea how to do this]

Answer 1

Answer:

We have 16 ounces of 3% H2O2

How many ounces of 30% H2O2 do we add to make a 10% H2O2 solution?

let x = amount of ounces of 30% H2O2 to add

.03 * 16 + .30x = .10 * (16 + x)

.48 + .30x = 1.6 + .1x

.2x = 1.12

x = 5.6 ounces

Source:

https://www.1728.org/mixture.htm

Step-by-step explanation:

Answer 2

Answer:

5.6 ounces of 30% H₂O₂ solution should be added.

Step-by-step explanation:

Let x ml of 30% H₂O₂ solution should be added with 10% H₂O₂ solution to get 3% H₂O₂ solution.

Volume of 3% H₂O₂ solution = 16 ounces

Volume of 10% H₂O₂ solution after mixing 30% H₂O₂ solution = (x + 16) ounces

Now equation will be

$x\times (\frac{30}{100})+16\times (\frac{3}{100})=(x+16)\times (\frac{10}{100} )$

0.3x + 0.48 = 0.10(x + 16)

0.3x + 0.48 = 0.10x + 1.6

0.3x = 0.10x + 1.6 - 0.48

0.3x - 0.10x = 1.6 - 0.48

0.20x = 1.12

x = $\frac{1.12}{0.2}$

  = 5.6 ounces