Ask question

Ask question

All categories

3 years ago

11

in January, Dawn earns $9.25 allowance. She earns 3 times as much in February. If during March, she earns $5.75 more than she di

d in February, how much allowance does Dawn earn in March?

2 answers:

AURORKA [14]3 years ago

8 0

Jan: 9.25
Feb: 9.25 x 3 = 27.75
March: 27.75 + 5.75 = 33.50

Dawn earns $33.50

Yuki888 [10]3 years ago

4 0

Dawn earns $33.5 in March because $9.25x3=$27.75 and $27.75+$5.75=$33.5.

Hope that helped:)

You might be interested in

What’s the answer for #11 @HavannaS? Spent 20 min and clueless, thank you!!!!!!

Elis [28]

Angle 2=3, so angle 1=4 because angles ABC & BCD equal 90°. When you add together the angles of a triangle you get 180 and if you could put angle 1 and 4 together it would look like an upward version.

That is the best way I could describe it. Hope that helps.

8 0

3 years ago

Please help me this question

ANTONII [103]

Answer:

0

Step-by-step explanation:

bcoz 2^5 X 9²=2592

so the difference is 0

5 0

3 years ago

Read 2 more answers

-6 - 3(2x + 4) = 18what’s the answer

Brrunno [24]

Answer:

$x=-6$

Step-by-step explanation:

$-6-3\left(2x+4\right)=18$

Add 6 to both sides:

$-6-3\left(2x+4\right)+6=18+6$

$-3\left(2x+4\right)=24$

Divide both sides by -3:

$\frac{-3\left(2x+4\right)}{-3}=\frac{24}{-3}$

$2x+4=-8$

Subtract 4 from both sides:

$2x+4-4=-8-4$

$2x=-12$

Divide both sides by 2:

$\frac{2x}{2}=\frac{-12}{2}$

$x=-6$

7 0

3 years ago

Given: △EDN∼△LKI, DQ , KO are altitudes, DN=12, KI=4, DQ=KO+6. Find: QN and OI.

fgiga [73]

Answer:

QN = 3√7
OI = √7

Step-by-step explanation:

The ratio of corresponding sides DN and KI is 12 : 4 = 3 : 1. The same ratio applies to altitudes DQ and KO. Since the difference between these altitudes is 6 and the difference between their ratio units is 3-1 = 2, each ratio unit must stand for 6/2 = 3 units of linear measure. That is, ...

DQ = (3 units)·3 = 9 units

KO = (3 units)·1 = 3 units

Then the base lengths QN and OI can be found from the Pythagorean theorem:

KI² = KO² +OI²

4² = 3² +OI²

OI = √(16 -9)

OI = √7

QN = 3·OI = 3√7

8 0

3 years ago

How do you you divide 67by6

Law Incorporation [45]

You first set it up as long division.
Second you would find out how many times 6 goes into 67, so count by 6's until you get close 67.
Third once you get that number you write it on top of the long division and then you would subtract whatever that number is below which is 66 because 6 * 11= 66.
So then you would subtract 67 minus 66 which would be 1. Then go from there and you'll get your answer.

Hope this helps!

6 0

3 years ago