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GalinKa [24]
3 years ago
7

What is the value of 3-(-2)?

Mathematics
2 answers:
My name is Ann [436]3 years ago
8 0

The answer is 5. If you subtract a negative number, you essentially add.

marysya [2.9K]3 years ago
4 0

Answer:

5

Step-by-step explanation:

When there is a “-“ in front of the parenthesis change the sign of each term in the parenthesis then add the numbers

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DOES SOMEONE UNDERSTAND THIS QUESTION???????????????
nikdorinn [45]

Answer:

Domain: T, from 0~80

Range: W, from 500~2500

Step-by-step explanation:

W = 25T + 500

T(Time) is from 0 to 80

So W(Water) is

When T = 0, W = 25*0 +500 = 500

When T = 80, W = 25*80 + 500 = 2500

4 0
3 years ago
How do i solve z+18=y
lubasha [3.4K]
<span>Simplifying z + 18 = y Reorder the terms: 18 + z = y Solving 18 + z = y Solving for variable 'z'. Move all terms containing z to the left, all other terms to the right. Add '-18' to each side of the equation. 18 + -18 + z = -18 + y Combine like terms: 18 + -18 = 0 0 + z = -18 + y z = -18 + y Simplifying z = -18 + y</span>
4 0
4 years ago
Which table contains only values that satisfy the equation y = -x +7?
a_sh-v [17]

Answer:

the question you typed is wrong but that on the picture is correct and the correct table which satisfied the equation y =1/4x + 7 is table C

7 0
3 years ago
Price of an article is 400 and sold with discount including 13% vat at 339 find discount rate
zvonat [6]
To add 13% vat we can multiply by (100%+13%) = 113% = 1.13
To remove 13% vat divide by 1.13
339 / 1.13 = 300 the discounted price.
The amount of discount = 400 - 300 = 100
Discount rate = 100 / 400 = 1/4 = 25%
3 0
2 years ago
Una poblacion es atacada por una epidemia de gripe sea N(t)= numero de personas enfermas al tiempo t. En dias la epidemia inicio
Lisa [10]

Answer:

<em>Habrán 10175 enfermos a los 15 dias.</em>

Step-by-step explanation:

La tasa de cambio de la población enferma por la epidemia de gripe es:

N'(t)=120t-3t^2

Donde t es el tiempo en dias, y se sabe que la epidemia inició en N(0)=50.

a)

Para encontrar la función original que describe el comportamiento de la epidemia, debemos integrar la función:

N(t)=\int N'(t)dt

N(t)=\int (120t-3t^2)dt

Integrando:

\displaystyle N(t)=120\frac{t^2}{2}-3\frac{t^3}{3}+C

Simplificando:

\displaystyle N(t)=60t^2-t^3+C

Para determinar el valor de C, usamos la condición inicial N(0)=50:

\displaystyle 50=60(0)^2-(0)^3+C

Se tiene que C=50, y la función queda determinada como:

\displaystyle N(t)=60t^2-t^3+50

b) El número de enfermos a los t=15 dias se determina substituyendo el valor en la función original:

\displaystyle N(15)=60(15)^2-(15)^3+50

Calculando:

N(15)=13500-3375+50=10175

Habrán 10175 enfermos a los 15 dias.

8 0
3 years ago
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