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svp [43]
3 years ago
9

Todd had 6 gallons of gasoline in his motorbike. After driving 150​ miles, he had 3 gallons left. Compute the​ slope, or rate of

change in the amount of gasoline.
Mathematics
2 answers:
yarga [219]3 years ago
8 0
So for every gallon he can drive 50 miles. So I think  the slope would be 50/-1
uranmaximum [27]3 years ago
8 0

Solution :

Give that,

Todd had 6 gallons of gasoline in his motorbike.After driving 150​ miles, he had 3 gallons left.

When Todd had 6 gallons of gasoline in his motorbike he drived 0 miles,

And When he had 3 gallons left , he had drived 150 miles.

Slope or rate of change = \frac{3-6}{150-0} =\frac{-3}{150} =-\frac{1}{50}  = - 0.02

Slope or rate of change of gasoline is negative which means gasoline is decreasing with increase in miles.

Slope or rate of change of gasoline= - 0.02 gallons/mile


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Genrish500 [490]

Answer:

  37.7 mi²/h

Step-by-step explanation:

The area formula is ...

  A = πr²

Differentiating with respect to time gives ...

  dA/dt = 2πr·dr/dt

Filling in the given values, we have ...

  dA/dt = 2π(3 mi)(2 mi/h) = 12π mi²/h

The area is increasing at the rate of about 37.7 mi² per hour.

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2 years ago
Yohan Blake ran the 100-meter race in the 2012 Olympics in 9.75 seconds. Compare the speeds if he ran the 200-meter race in 19.5
lakkis [162]

Sorry for the late response :<

Answer:

The unit rates would be comparable for both races. So, his speed is going to be the same for both races.

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8 0
2 years ago
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Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL
Tems11 [23]

Answer:

Yes they are

Step-by-step explanation:

In the triangle JKL, the sides can be calculated as following:

  • J(2;5); K(1;1)

             => JK = \sqrt{(1-2)^{2} + (1-5)^{2}  } = \sqrt{(-1)^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • J(2;5); L(5;2)

             => JL = \sqrt{(5-2)^{2} + (2-5)^{2}  } = \sqrt{3^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • K(1;1); L(5;2)

             =>  KL = \sqrt{(5-1)^{2} + (2-1)^{2}  } = \sqrt{4^{2}+1^{2}  } = \sqrt{1+16}=\sqrt{17}

In the triangle QNP, the sides can be calculate as following:

  • Q(-4;4); N(-3;0)

             => QN = \sqrt{[-3-(-4)]^{2} + (0-4)^{2}  } = \sqrt{1^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • Q (-4;4); P(-7;1)

   => QP = \sqrt{[-7-(-4)]^{2} + (1-4)^{2}  } = \sqrt{(-3)^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • N(-3;0); P(-7;1)

             =>  NP = \sqrt{[-7-(-3)]^{2} + (1-0)^{2}  } = \sqrt{(-4)^{2}+1^{2}  } = \sqrt{16+1}=\sqrt{17}

It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

=> They are congruent triangles

7 0
3 years ago
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What is the gcf In this problem
scoray [572]
Find the GCF of 88 and 24 first 

88=2*2*2*11 
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The GCF for 88 and 24 is 8 
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Hope I helped :) 
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Step-by-step explanation:

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For the sake of ease just multiply 2/6 by 2, this will equal 4/12 NOT 5/12

Hope this helps! :)

6 0
3 years ago
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