I need help on finding the variable and answer

What is the reflection of point P (-1,6) across the line y=x

vesna_86 [32]

It will be -1 and -6 because you would move down 12 times

4 0

4 years ago

Please answer correctly !!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!

GalinKa [24]

Answer:

{12, 16, 20}

Step-by-step explanation:

12×12+16×16=20×20

pythagorean theorem

4 0

3 years ago

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Find the cdf F(x) associated with each of the following probability density functions. Sketch the graphs of f(x) and F(x).

wolverine [178]

Answer:

See steps below

Step-by-step explanation:

a)

$\bf f(x)=3(1-x)^2\;(0$

$\bf F(x)=\int_{0}^{x}f(t)dt=\int_{0}^{x}3(1-t)^2dt=3\int_{0}^{x}(1-t)^2=1-(1-x)^3$

The cdf associated with f is

$\bf \boxed{F(x)=1-(1-x)^3}$ for 0<x<1

<h3>See picture 1 </h3>

The median is a point x such that

F(x) = ½

so, the median is

$\bf 1-(1-x)^3=1/2\rightarrow (1-x)^3=1/2\rightarrow \boxed{x=1-\sqrt[3]{2}}$

The 25th percentile equals the 1st quartile and is a point x such

F(x) = ¼

and the 25th percentile is

$\bf 1-(1-x)^3=1/4\rightarrow (1-x)^3=3/4\rightarrow \boxed{x=1-\sqrt[3]{3/4}}$

b)

$\bf f(x)=\frac{1}{x^2}\;(1$

$\bf F(x)=\int_{1}^{x}f(t)dt=\int_{1}^{x}\frac{dt}{t^2}=1-\frac{1}{x}$

The cdf associated with f is

$\bf \boxed{F(x)=1-\frac{1}{x}}$ for x>1

<h3>See picture 2 </h3>

The median is

$\bf 1-\frac{1}{x}=\frac{1}{2}\rightarrow \boxed{x=2}$

The 25th percentile is

$\bf 1-\frac{1}{x}=\frac{1}{4}\rightarrow \boxed{x=4/3}$

c)

f(x) = 1/3 for 0<x<1 or 2<x<4

$\bf F(x)=\int_{0}^{x}\frac{dt}{3}=\frac{x}{3}\;(0$

$\bf F(x)=\frac{1}{3}+\int_{2}^{x}\frac{dt}{3}=\frac{1}{3}+\frac{x-2}{3}=\frac{x-1}{3}\;(2$

The cdf associated with f is

$\bf F(x)=\frac{x}{3}$ for 0<x<1

$\bf F(x)=\frac{x-1}{3}$ for 2<x<4

<h3>See picture 3 </h3>

The median is

$\bf \frac{x-1}{3}=1/2\rightarrow x=1+3/2\rightarrow \boxed{x=5/2}$

The 25th percentile is

$\bf \frac{x}{3}=1/4\rightarrow \boxed{x=3/4}$

4 0

4 years ago

What is the volume, in cubic m, of a cube with an edge length of 11m?

rewona [7]

the volume of cube with edge length 11 m is $Volume = 1331m^3$ .

<u>Step-by-step explanation:</u>

Here we have a side length of a cube as 11 m . We need to find the volume of cube . Let's find out:

We know that every side of a cube is identical and equal . And volume of cube is given by formula :

⇒ $Volume = (side)^3$ ...........(1)

According to question we have following parameters as

$side = 11m$

Putting this in (1)

⇒ $Volume = (11m)^3$

⇒ $Volume = 11(11)(11)m^3$

⇒ $Volume = (121)(11)m^3$

⇒ $Volume = 1331m^3$

Therefore , the volume of cube with edge length 11 m is $Volume = 1331m^3$ .

3 0

3 years ago

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FR.EE POINTS HAVE A GOOD DAY 100PTS :)

Law Incorporation [45]

Answer:

Thank u so much have a good day too

5 0

3 years ago

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