Answer:
The range of the 95% data (X) = 238.3 days < X < 289.9 days
Step-by-step explanation:
Given;
mean of the normal distribution, m = 264.1 days
standard deviation, d = 12.9 days
between two standard deviation below and above the mean is 96% of all the data.
two standard deviation below the mean = m - 2d
= 264.1 - 2(12.9)
= 238.3 days
two standard deviation above the mean = m + 2d
= 264.1 + 2(12.9)
= 289.9 days
The middle of the 95% of most pregnancies would be found in the following range;
238.3 days < X < 289.9 days
7 (6) + 14!!! And this needs to be 20 characters long so I’m adding this
Answer: the answer is 64 1/3
Step-by-step explanation:
The number of calculators
= Number of boxes * calculators in each box
=18* 12
= 216 calculators
Radius = 100m
Circumference of a circle = 2πr
= 2 × π× 100
=628.31m
