Answer:
12m²
Step-by-step explanation:
For a rectangle, with length L and width W,
the perimeter is given as
Perimeter,
P = (2 x Length) + (2 x Width)
P = 2L + 2W
It is given that the perimeter is 48, hence
48 = 2L + 2W (divide both sides by 2)
24 = L + W
or
L = 24 - W -----> eq 1
Also realize that the Area of a Rectangle is given by
A = L x W -----> eq 2
Substituting eq 1 into eq 2,
A = (24 - W) x W
A = -W² + 24W
Recall that for a quadratic equation y = ax² + bx + c, the maxima or minima is given by y(max) = -b/2a
In this case, b = 24 and a = -1
-b/2a = -24/[ 2(-1) ] = 12
Hence for A to be maximum A(max) = 12m² (Answer)
1) Area = leg(1) * leg(2) * .5 = 15 * 36 * .5 = 270
Perimeter = leg(1) + leg(2) + hypotenuse = 15 + 36 + 39 = 90
2) Area = leg(1) * leg(2) = 20 * 80 = 1600
3) Median (divides it in 1/2)
4) Both (divides it in 1/2 and makes a 90 degree angle w/ base)
5) Altitude (makes 90 degree angle w/ base)
6)sqrt(30^2 + 16^2) = sqrt( 900 + 256) = sqrt(1156) = 34
7) sqrt(24^2 + 18^2) = sqrt( 576 + 324) = sqrt(900) = 30
8) sqrt(40^2 + 96^2) = sqrt(1600 + 9216) = sqrt(10816) = 104
9) sqrt(150^2 - 90^2) = sqrt(22500 - 8100) = sqrt(14400) = 120
10) sqrt(35^2 - 25^2) = sqrt(1225 - 625) = sqrt(600) = 10sqrt(6), approx. 24.5
Answer:
The slope of a line that has a y-intercept but no x-intercept will be zero.
Step-by-step explanation:
If the line has no x-intercept, then it never intersects the x-axis, so it must be parallel to the x-axis.
If a line does not have an x-intercept, it means it would never intersect the x-axis.
Thus, it must be parallel to the x-axis, meaning its slope will be zero. It would be just a horizontal line.
For example, y=9 is the line equation that does not have an x-intercept and its slope is zero.
Therefore, the slope of a line that has a y-intercept but no x-intercept will be zero.
