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Ira Lisetskai [31]
2 years ago
14

If x^2y^3=10 and x^3y^2=8, what is the value of x^5y^5

Mathematics
1 answer:
arlik [135]2 years ago
3 0

Answer:

80.

Step-by-step explanation:

x^2y^3 * x^3y^2

= x^(2+3)y^(3+2)

= x^5y^5     and as x^2y^3 = 10 and x^3y^2 = 8 we have:

10 * 8  

= 80.

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D(1)=3 d(n) = d(n-1) - 14 what is the third term in the sequence
Aliun [14]
2nd term  =  3 - 14 = -11
3rd tern = -11-14 = -25 answer
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Find the quotient of 191 divided by 5
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Lily saved 16 coins. She saved ten-can and one-dollar coins only. If she had $5.20, how many ten-cent coins did she have?
Firlakuza [10]

Answer:

  12

Step-by-step explanation:

Let d represent the number of dimes Lily saved. Then the value of her coins in cents is ...

  10d +100(16-d) = 520

  -90d +1600 = 520 . . . . . eliminate parentheses, collect terms

  -90d = -1080 . . . . . . . . . . subtract 1600

  d = -1080/-90 = 12 . . . . . divide by the coefficient of d

Lily has 12 ten-cent coins.

4 0
3 years ago
Can someone help me with this problem://
fiasKO [112]

You can simply collect terms, subtract the constant and divide by the x-coefficient. It is generally considered easier to do those steps if you eliminate fractions first (multiply by 12).

Multiply by 12

... 4(x -1) +3(x +5) = 6

... 4x -4 +3x +15 = 6 . . . . . eliminate parentheses

... 7x +11 = 6 . . . . . . . . . . . .collect terms

... 7x = -5 . . . . . . . . . . . . . . subtract the constant 11

... x = -5/7 . . . . . . . . . . . . . divide by the x-coefficient

_ _ _ _ _ _ _

Here it is the other way.

... x(1/3 +1/4) +(-1/3 +5/4) = 1/2

... (7/12)x + 11/12 = 1/2 . . add the fractions to finish collecting terms

... x + 11/7 = 6/7 . . . . . . . multiply by 12/7

... x = -5/7 . . . . . . . . . . . subtract 11/7

At the third step here, you could subtract 11/12 before doing the multiply. You get the same answer, but you have to do the extra conversion of 1/2=6/12.

8 0
3 years ago
Below are the rates of travel of 4 shipping trucks. Which truck drove the fastest rate? Truck A: 300 miles in 4 hours Truck B: 2
Tasya [4]

Answer:

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Step-by-step explanation:

Below are the rates of travel of 4 shipping trucks.

Truck A: 300 miles in 4 hours Truck B: 240 miles in 3 hours Truck C: 325 miles in 5 hours Truck D: 170 miles in 2 hours.

Speed = distance/time

Speed of Truck A,

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Speed of Truck B,

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Speed of Truck C,

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v_D=\dfrac{170}{2}\\\\v_D=85\ mph

It can be seen that the speed of Truck D is more out of Trucks A,B and C. Hence, Truck D is moving at a faster rate.

8 0
2 years ago
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