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sdas [7]
2 years ago
12

An arc of length 8 in. is intersected by a central angle in a circle with a radius of 3 in. What is the measure of the angle? Ro

und your answer to the nearest tenth.
Mathematics
2 answers:
Mandarinka [93]2 years ago
5 0

Answer: 2.7 radians.

Step-by-step explanation:

The formula we use to find the length of the arc :-

l=\theta r , where \theta is the measure of the central angle  (in radians )and r is the radius .

Given : An arc of length 8 in. is intersected by a central angle in a circle with a radius of 3 in.

i.e. l= 8 in.  and r = 3 in.

From the above formula , we have

8=\theta (3)\\\\\Rightarrrow\ \theta=\dfrac{8}{3}=2.66666666667\approx2.7\text{ radians}  [Rounded to the nearest tenth.]

Hence, the measure of the angle = 2.7 radians.

sergey [27]2 years ago
4 0

Answer:

2.7 radians

have a nice day :)

Step-by-step explanation:

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Answer:

Step-by-step explanation:

Domain of a function represents the set of x-values (input values) and y-values (output values) of the function represent the Range of the function.

Given function is,

If Domain (input values) of this function is,

{-12, -6, 3, 15}

Table for the input-output values of this function,

x        -6         3        15       -12

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What is 8 divided by 3/4s
d1i1m1o1n [39]
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7 0
3 years ago
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ira [324]

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Step-by-step explanation:

8 0
3 years ago
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ziro4ka [17]

Yo sup??

This question can be solved by applying the properties of similar triangles

the triangle with sides 5x and 20 is similar to the triangle with sides 45 and 35

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7 0
2 years ago
"A student made the following chart to prove that AB2 + BC2 = AC2.
katovenus [111]

Step 3 has an error.

Step-by-step explanation:

Similarity-criteria of triangles:

1. All the corresponding angles of two triangles should be equal.

2. The ratio between the corresponding sides of two triangles should be equal.

In \triangle ABC and \triangle BDC  

\angle BAC = \angle DBC \\\angle ACB = \angle BCD

All the angles of triangle are equal.

∴\triangle ABC \sim \triangle BDC

Since, \triangle ABC \sim \triangle BDC

\frac{AC}{BC}=\frac{AC}{DC}

BC^{2}=AC \times DC

In \triangle ABC and \triangle BDA,

\fbox{\begin\\ \angle ABC= \angle BDA = 90^{\circ}\end{minispace}}

\fbox{\begin \\\angle BAC = \angle BAD\\\end{minispace}}

\angle ACB = \angle ABD

All the angles of triangle are equal.

∴\fbox{\begin\triangle ABC \sim \triangle BDA \end{minispace}}

∵\triangle ABC \sim \triangle BDA  

\frac{AC}{AB}=\frac{AB}{AD}

AB^{2}=AC \times AD

Now, AB^{2}+BC^{2} can be simplified as,

AB^{2}+BC^{2}=AC \times AD+AC \times DC\\AB^{2}+BC^{2}=AC(AD+DC)\\AB^{2}+BC^{2}=AC(AC)\\AB^{2}+BC^{2}=AC^{2}

Learn more:

1. Find the height of the triangle?

brainly.com/question/12989306

2. Which undefined term is needed to define an angle? brainly.com/question/3717797

3. Look at the figure, which trigonometric ratio should you use to find x? brainly.com/question/9880052

Answer Details

Grade: Junior High School

Subject: Mathematics

Chapter: Triangle

Keywords: triangle, similar, similarity, ratio of sides, right triangle, similar triangle, ratio of sides, equal angles, square of hypotenuse, sum, square of legs, sum of square of legs

8 0
3 years ago
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