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erica [24]
3 years ago
13

HELP PLEASE!!!!! ASAP!!!! 20 POINTS!!!!!

Mathematics
1 answer:
inessss [21]3 years ago
6 0

Answer:wg

Step-by-step explanation:

wg

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Order the set of integers from least to greatest.
Bogdan [553]

Answer:Hi

Step-by-step explanation: like this comment for good luck

7 0
3 years ago
Alice wants to buy 3 pounds of veal at the grocery store, but the scales at the store only show weight in kilograms. If one kilo
kaheart [24]

Alice should buy 1.36 kilograms of veal.

Step-by-step explanation:

Given,

According to store's scale;

2.20 pounds = 1 kilogram

1 pound = \frac{1}{2.20}\ kg

As Alice wants to buy 3 pounds, therefore,

3 pounds = \frac{1}{2.20}*3\\

3\ pounds = \frac{3}{2.20}\\3\ pounds = 1.36\ kg

Alice should buy 1.36 kilograms of veal.

Keywords: unit rate, fractions

Learn more about fractions at:

  • brainly.com/question/11286417
  • brainly.com/question/12896802

#LearnwithBrainly

3 0
4 years ago
Read 2 more answers
Solve for x.<br> 3(x+3) = -18 . A. x= -9<br> B.x= -7<br> c. x=-5<br> D. X=-3
slavikrds [6]

It is A x= -9 I just did the assignment so yes, this means it is -9 I hope m answer helps you out.

3 0
3 years ago
Eduardo thinks of a number between 1 and 20 that has exactly 5 factors.Which number is he thinking of?
Dimas [21]
Your answer is 16: 1,2,4,8,16
8 0
3 years ago
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Suppose the claim size of an auto collision insurance, X, is uniformly distributed on the interval $1,000 to $10,000. What is th
timurjin [86]

Answer:

35.35%

Step-by-step explanation:

If there were no deductibles, the expected claim payment would be:

E(X) = \frac{10,000 +1,000}{2} \\E(X) =\$5,500

If the collision insurance claim is under $2,000, then the insurer would not pay anything, but if X > $2,000, then the insurer would pay X - $2,000. The new expected value is:

E_2(X)=\frac{2,000-1,000}{10,000-1,000} *0+\frac{10,000-2,000}{10,000-1,000}*\frac{(2,000-2,000)+(10,000-2,000)}{2} \\E_2(X)=\frac{8}{9}*\frac{0+8,000}{2}\\ E_2(X)=\$3,555.56

The percentage reduction on the claim payment is:

P=(1-\frac{E_2(X)}{E(X)})*100 \\P=(1-\frac{3,555.56}{5,500})*100\\P=35.35\%

There was a 35.35% reduction.

8 0
4 years ago
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