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son4ous [18]
3 years ago
12

What is the axis of symmetry of the graph of function f(X) = X2 - 10X +16

Mathematics
2 answers:
igor_vitrenko [27]3 years ago
6 0

Answer:

x = 5

Step-by-step explanation:

That's f(x) = x^2 - 10x + 16.  The coefficients of the x terms are {1, -10, 16}:  {a, b, c}.  

                                                                         -b

The formula for the axis of symmetry is x = --------

                                                                           2a

Here, with a = 1 and b = -10, the formula for this particular axis of symmetry is

       -(-10)

x = ------------ = 5

         2(1)

or x = 5

3241004551 [841]3 years ago
3 0

Answer:

Axis of Symmetry: x=5

Step-by-step explanation:

The axis of symmetry is defined as the line x=\frac{-b}{2a}. Therefore, our axis of symmetry is located at the line x=\frac{-(-10)}{2(1)}=\frac{10}{2}=5. See the graph attached for a visual.

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54 is the sum of 11 and raj's score
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Answer:

54 is the sum of 11 and Raj's age. Use variable "r" to represent Raj's age

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3 years ago
What is the quotient 2y^-6y-20/4y+12 ÷ y+5y+6/3y^2+28y+27​
malfutka [58]

Answer with explanation:

 \rightarrow \frac{\frac{2y^2-6 y-20}{4 y+12}}{\frac{y^2+5 y+6}{3 y^2+28 y+27}}\\\\\rightarrow \frac{\frac{y^2-3y-10}{2 y+6}}{\frac{(y+2)(y+3)}{3 y^2+28 y+27}}\\\\\rightarrow \frac{\frac{(y-5)(y+2)}{2 (y+3)}}{\frac{(y+2)(y+3)}{3 y^2+28 y+27}}\\\\\rightarrow \frac{(y-5)(y+2)}{2 (y+3)}} \times {\frac{3 y^2+28 y+27}{(y+2)(y+3)}}\\\\ \rightarrow\frac{(y-5)\times(3 y^2+28 y+27)}{2 (y+3)^2}}

→y²+5y+6

=y²+3 y+2 y+6

=y×(y+3)+2×(y+3)

=(y+2)(y+3)

→y² -3 y-10

=y² -5 y+2 y -10

=y×(y-5)+2×(y-5)

=(y+2)(y-5)

6 0
3 years ago
Read 2 more answers
What is the radius of a circle whose equation is x2 + y2 + 8x - 6y + 21 = 0?<br> units
pickupchik [31]

Answer:r=2

Step-by-step explanation:

6 0
3 years ago
Helpppp now please helpppp
algol [13]
The correct answer is:  [B]:  " \frac{(-3)(4)}{(6)} " . 
__________________________________________________________
Consider choice [A]:  \frac{(3)(4)}{(6)} ; 
                              = \frac{12}{6} ; 
                              = 2 ;  "2 ≠ -2" ; so we can rule out:  "Choice [A]" .
__________________________________________________________
Consider choice [B]:  \frac{(-3)(4)}{(6)} ; 
                              = \frac{-12}{6} ; 
                              =  "-2" ;  Yes!
→ Let us proceed with the final answer choice ;
__________________________________________________________
Consider choice [C]:  \frac{(-3)(-4)}{(6)} ; 
                              = \frac{12}{6} ; 
                              = 2 ;  "2 ≠ -2" ; so we can rule out:  "Choice [C]" .
__________________________________________________________
The correct answer is:  [B]:  " \frac{(-3)(4)}{(6)} "  .
__________________________________________________________
7 0
3 years ago
Please help.<br> Is algebra.
Vlad1618 [11]
? = 2. Thats the only one i got that equals 8xy^2. Not sure if its right tho.
4 0
3 years ago
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