m∠FDE = 52°
Solution:
Given data:
DE ≅ DF, CD || BE, BC || FD and m∠ABF = 116°
<em>Sum of the adjacent angles in a straight line = 180°</em>
m∠ABF + m∠CBF = 180°
116° + m∠CBF = 180°
m∠CBF = 64°
If CD || BE, then CD || BF.
Hence CD || BE and BE || FD.
Therefore BFCD is a parallelogam.
<em>In parallelogram, Adjacent angles form a linear pair.</em>
m∠CBF + m∠BFD = 180°
64° + m∠BFD = 180°
m∠BFD = 116°
<em>Sum of the adjacent angles in a straight line = 180°</em>
m∠BFD + m∠DFE = 180°
116° + m∠DFE = 180°
m∠DFE = 64°
we know that DE ≅ DF.
<em>In triangle, angles opposite to equal sides are equal.</em>
m∠DFE = m∠DEF
m∠DEF = 64°
<em>sum of all the angles of a triangle = 180°</em>
m∠DFE + m∠DEF + m∠FDE = 180°
64° + 64° + m∠FDE = 180°
m∠FDE = 52°
Answer:
a.
Loan I's increase was 0.03 percentage points greater than Loan H's
Answer:
4n+2
Step-by-step explanation:
- add all sides =9n+3
- 3n+2+2n-1=9n+3
- add liketerms 5n+1=9n+3
- put liketerms together 9n-5n+3-1
- ans hence is 4n+2
<span>you can solve all quadratic equations using this method:
---
x^2 + 4x + 4 = 0
---
the above quadratic equation is in standard form, with a=1, b=4, and c=4
---
to solve the quadratic equation, by using the quadratic formula, copy and paste this:
1 4 4
into this solver: https://sooeet.com/math/quadratic-equation-solver.php
---
this quadratic has ONE real root (the x-intercept), which is:
x = -2
x = -2
---
---
---
---
x^2 + x = 0
---
the above quadratic equation is in standard form, with a=1, b=1, and c=0</span>
U = 1
L = 0
R = -2
I = 24
M = 17
H = -3
E = 100
S = -439
O = 11
B = -6
T = -41
D = 19
C = 206
<em>Hope this helped ! :)</em>
