False because x can only have one y or an input can only have one output. 3 has two outputs and so does 2 so this is not a function.
Answer:
= 2x
Step-by-step explanation:
Answer:
b/7=-5
b=-5×7
b=-35
Step-by-step explanation:
2.c/8-(-9)=18
c/8+9=18
c/8=18-9
c/8=9
c=9×8
c=72
Answer:
Discriminant: -4
No real solutions
Step-by-step explanation:
You might remember this long, seemingly very hairy thing called the <em>quadratic formula</em> from earlier in algebra:
![x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7B-b%5Cpm%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D)
The <em>discriminant</em> of a quadratic equation of the form
is that bit under the square root:
. What does the discriminant tell us? Since we're taking its square root, we know that
is only real for non-negative values of
. If
, we have two real roots, one for
and one for
. If
, the function has a rational root, since the formula becomes
![x=\frac{-b}{2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%7D%7B2a%7D)
In your case, we have the equation
; here,
,
, and
, so our discriminant is
. Since we'd have a negative under our square root in the quadratic formula, we have <em>no real solutions</em>.
Answer:
576
Step-by-step explanation:
We want to evaluate
for a= 2 , b= 3 and c= 4.
We just have to substitute for a= 2 , b= 3 and c= 4 into
and simplify.
This implies that:
![a^2b^2c^2=2^2*3^2*4^2](https://tex.z-dn.net/?f=a%5E2b%5E2c%5E2%3D2%5E2%2A3%5E2%2A4%5E2)
![a^2b^2c^2=4*9*16](https://tex.z-dn.net/?f=a%5E2b%5E2c%5E2%3D4%2A9%2A16)
![a^2b^2c^2=576](https://tex.z-dn.net/?f=a%5E2b%5E2c%5E2%3D576)
Therefore
for a= 2 , b= 3 and c= 4