PLEASE HELP!!! WILL REWARD!!

Mathematics

2 answers:

Elena L [17]3 years ago

7 0

Answer:

x+y+z-2t

Step-by-step explanation:

There are t students taking all three and the rest take only 1 language.

The number taking only Oriya is x-t .

The number taking only Dakhini is y-t .

The number taking only Dutch is z-t .

So the number of students altogether is

x-t + y-t + z-t + t = x+y+z-2t.

Hope this helps! :D

BabaBlast [244]3 years ago

3 0

X+y+z=t
simple..
there are no other numbers that we have to follow like (1/2x or 3/4y) so it is just all together=t. the x, y, z will equal t because t is the total number of students taking three languages. And that number should be equivalent to x,y,z combined.

otherwise?? i d k<span />

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SOMEONE HELP ASAPPPPPPP!!! PLEASE

Rom4ik [11]

(1) See below for a diagram. Basically, the distance on the ground from the person to the building (34 ft) is adjacent to the angle of elevation (74 degrees) and the height of the building (labeled h in the diagram) is the side opposite the angle. Since we are dealing with opposite and adjacent we use the tangent of the angle and tan = opp/adj

Specifically, $tan74= \frac{h}{34}$
$h=(34)(tan74)$ <span class="_wysihtml5-temp-placeholder"></span>
$h=118.6$ feet.

Please be sure your calculator is set to degrees (not radians) when you do this problem.

(2) Here since P & Q are complimentary it means that their sum is 90 degrees. Since this is a right triangle that means that the remaining angle (R) must be the right angle. See below for a diagram.

sin = opp/hyp. As the sin Q = 9/41 this means that 9 is the length of the side opposite Q (the side PR) and 41 is the length of the hypotenuse. This makes the remaining side (QR) 40 in length.

cos = adj/hyp. If we focus on angle P the side adjacent (next to) is 9 and the hypotenuse is 41. Thus the cos of P = 9/41.

You could have also realized that if P & Q are complimentary the sin P = cos Q and the cos P = sin Q. We were not asked about tangent but it is also the case that tan P = cot Q and cot P = tan Q.