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zysi [14]
3 years ago
7

Simplify 3x - 4 - 5x = 6 + 4x + 2

Mathematics
2 answers:
qaws [65]3 years ago
7 0
The answer is x = -2
olga2289 [7]3 years ago
3 0

Answer:

x=(−2)

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

Step 2: Subtract 4x from both sides.

Step 3: Add 4 to both sides.

Step 4: Divide both sides by -6.

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Bogdan [553]

Answer:

there is nothing on here

Step-by-step explanation:

5 0
3 years ago
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the length of a pool 2 km long is represented on a map with a length of 20cm. what is the map scale used?​
goldenfox [79]

Answer:

The scale used is 1: 10,000 cm.

Step-by-step explanation:

Given that the length of a pool 2 km long is represented on a map with a length of 20cm, to determine what is the map scale used the following calculation must be performed:

2 km = 2,000 m

1m = 100cm

2,000 x 100 = 200,000

20: 200,000

10: 100,000

1: 10,000

Thus, the scale used is 1: 10,000 cm.

4 0
3 years ago
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Oliver uses the greatest common factor and the distributive property to rewrite this sum:
dalvyx [7]
The greatest common factor of 64 and 96 is 32, so, the first step after finding the great common factor is convert and rewrite "64 + 96" into distributive property. 

You should get 32(2 + 3)
7 0
3 years ago
Trigonometry help!! - double angle formulae
ivolga24 [154]

Answer:

The two rules we need to use are:

Sin(a + b) = sin(a)*cos(b) + sin(b)*cos(a)

cos(a + b) = cos(a)*cos(b) - sin(a)*sin(b)

And we also know that:

sin^2(a) + cos^2(a) = 1

To solve the relations, we start with the left side and try to construct the right side.

a) Sin(3*A) = sin (2*A + A) = sin(2*A)*cos(A) + sin(A)*cos(2*A)

sin(A + A)*cos(A) + sin(A)*cos(A + A)

(sin(A)*cos(A) + sin(A)*cos(A))*cos(A) + sin(A)*(cos(A)*cos(A) - sin(A)*sin(A))

sin(A)*cos^2(A) + sin(A)*cos^2(A) + sin(A)*cos^2(A) - sin^3(A)

3*sin(A)*cos^2(A) - sin(A)*sin^2(A)

sin(A)*(3*cos^2(A) - sin^2(A))

Now we can add and subtract 4*sin^3(A)

sin(A)*(3*cos^2(A) - sin^2(A)) + 4*sin^3(A) -  4*sin^3(A)

sin(A)*(3*cos^2(A) + 3*sin^2(A)) - 4*sin^3(A)

sin(A)*3*(cos^2(A) + sin^2(A)) - 4*sin^3(A)

3*sin(A) - 4*sin^3(A)

b) Here we do the same as before:

cos(3*A) = 4*cos^3(A) - 3*cos(A)

We start with:

Cos(2*A + A) =  cos(2*A)*cos(A) - sin(2*A)*sin(A)

= cos(A + A)*cos(A) - sin(A + A)*sin(A)

= (cos(A)*cos(A) - sin(A)*sin(A))*cos(A) - ( sin(A)*cos(A) + sin(A)*cos(A))*sin(A)

= (cos^2(A) - sin^2(A))*cos(A) - sin^2(A)*cos(A) - sin^2(A)*cos(A)

= cos^3(A) - 3*sin^2(A)*cos(A)

=  cos(A)*(cos^2(A) - 3*sin^2(A))

now we subtract and add 4*cos^3(A)

= cos(A)*(cos^2(A) - 3*sin^2(A)) + 4*cos^3(A) - 4*cos^3(A)

= cos(A)*(-3*cos^2(A) - 3*sin^2(A)) + 4*cos^3(A)

= cos(A)*(-3)*(cos^2(A) + sin^2(A)) + 4*cos^3(A)

= -3*cos(A) + 4*cos^3(A)

8 0
3 years ago
Noel correctly answers 80% of the questions on a test with
adell [148]
40 x (80/100)
= 32
So answer will be 32
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