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4 years ago

Write the equation of the line that passes through the points (-9, -3) and (-7,7).

Mathematics

1 answer:

tiny-mole [99]4 years ago

6 0

Answer:

y=5x+42

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(7-(-3))/(-7-(-9))

m=(7+3)/(-7+9)

m=10/2

m=5

y-y1=m(x-x1)

y-(-3)=5(x-(-9))

y+3=5(x+9)

y=5x+45-3

y=5x+42

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What is the vertex of g(x) = 3x2 − 12x + 7?

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$\mathbf{Task.} ~ \mathrm{What~is~the~vertex~of}~ g(x) = 3x^{2} - 12x + 7?$

$\mathrm{Function~of~the~form} ~ f(x) = ax^{2} + bx + c, ~ a \neq 0, ~ \mathrm{is~ called~a~quadratic~function.}\\\mathrm{The~top} ~ (x_{0}; \ y_{0}) ~ \mathrm{of~this~function~can~be~found~by~the~formulas \colon}$

$x_{0} = \dfrac{-b}{2a};$

$y_{0} = ax_{0}^{2} + bx_{0} + c ~ \mathrm{or} ~ y_{0} = -\dfrac{b^{2} - 4ac}{4a}.$

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