Number of bricks = 12
Height of full tower = 27 inches
Height of one brick =
= 2.25 inch
B, because I’m A, it has no number to regroup from(all the numbers can go into each other when yo add) In B, 6 can’t go into 2, so you’ll need to regroup, - hopefully this helped and hopefully I get the answer correct
Answer:
Not Sure
Step-by-step explanation:
Here's something that might help though:
Do 8% of 20
Then 14% of 20
That's all I got for ya... sorry, I tried my best!
Answer:
nElements = 0;
for (int i = 0; i < a2d.length; i++)
nElements += a2d[i].length;
isRectangular = true;
for (int i = 1; i < a2d.length && isRectangular; i++)
if (a2d[i].length != a2d[0].length)
isRectangular = false;
Step-by-step explanation:
2 dimensional array is created and initialize element with 0. and the taking loop for 2 dimensional array .such as
n Elements = 0;
for (int i = 0; i < a2d.length; i++)
n Elements += a2d[i].length;
A boolean variable isRectangular and 2 dimensional array has been created if rectangle is true the take a2d.length and isRectangular less than i and intiliaze i with 1 then increment the i .It will give true value.
If rectangular is false then apply if statement and see if a2d[i] is not equal to a2d[0]
if (a2d[i].length != a2d[0].length)
isRectangular = false;
Answer: B
Step-by-step explanation:
Histogram is a statistical graph with the use of bar. The bar are not seperated unlike bar chart.
0.320 to 0.329 and 0.360 to 0.369 are of the same frequency which is equal to one. 0.350 to 0.359 is of frequency 2 a little above frequency 1.
Option B and D are very close to each other in value representation. But the frequency of 0.350 to 0.359 in option D is 3. This renders option D invalid and make option B the correct answer.
