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Gemiola [76]
3 years ago
12

Seth’s father is thinking of buying his son a six-month movie pass for $140. With the pass,matinees cost 1.00.If nastiness are n

ormally $3.50 each,how many times must Seth attend in order for it to benefit his father to buy the pass?
Mathematics
1 answer:
Gala2k [10]3 years ago
5 0

Answer:

40 shows

Step-by-step explanation:

Seth’s father has spent $140.  

At the regular price, the number (n) of shows Seth could attend is

n = 140/3.50

n = 40

If Seth attends 40 shows at that price, he will have spent $140.

Every show after that will cost only $1 instead of $3.50.

Seth must attend 40 shows for it to benefit his father.

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lara [203]
Since order is important...

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or if you prefer

12*11*10=1320
8 0
3 years ago
What’s the answer <br> A<br> B<br> C<br> D
zimovet [89]

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6 0
3 years ago
9 = 90, 8 = 72, 7 = 56, 6 = 42, 3 = ?
bulgar [2K]
The correct  answer according to me  is 3=12
7 0
3 years ago
Read 2 more answers
What is the 37th term of the arithmetic sequence with the first term -39 and the common difference of 8.
Mrrafil [7]

Answer:

a_{37}=249

Step-by-step explanation:

A sequence that has a common difference is an <em>arithmetic sequence</em>:

a_n=a_1+(n-1)d

where aₙ is the nth term, n is the index, and d is the common difference.

In your question:

  • n = 37
  • a₁ = -39
  • d = 8

Plug those into the formula:

a_{37}=-39+(37-1)8

Then solve:

a_{37}=-39+(36)8\\a_{37}=-39+288\\a_{37}=249

8 0
3 years ago
Please help me I’m not the smartest
Katyanochek1 [597]
(3x+1) + (2x+8) = 180
5x+9=180
5x=171
8 0
3 years ago
Read 2 more answers
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