Consider the <em>fraction</em> first ;




<em>Hence, Option B) is </em><em>required</em><em> </em><em>answer</em>
Answer:
Step-by-step explanation:
The translation vector < 4, - 2 > means each point is being moved 4 units to the right and 2 units down.
X(0, 3) ------> X' ( 0 + 4, 3 - 2 ) = X'(4, 1)
Y( - 1, 1) ------> Y' ( - 1 + 4, 1 - 2 ) = Y'(3, - 1)
Z( - 3, 4) -----> Z' ( - 3 + 4, 4 - 2 ) = Z'(1, 2)
X = 6
11-3x=-7
Subtract 11 from both sides.
-3x = -18
Divide -3 on both sides.
X = 6
If x is the price before a sale
x-0.15x=x-3
0.85x=x-3
3=0.15x
x=20
The original price is $20