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DaniilM [7]
3 years ago
11

The length of the longer side of rectangle $r$ is $10$ percent more than the length of a side of square $s.$ the length of the s

horter side of rectangle $r$ is $10$ percent less than the length of a side of square $s.$ what is the ratio of the area of rectangle $r$ to the area of square $s?$ express your answer as a common fraction.
Mathematics
1 answer:
liraira [26]3 years ago
7 0
Let
x-------------> length of the side of a square

[area of a square]=x*x------> x²

[area of rectangle]=[shorter side]*[<span>longer side]
</span>[shorter side]=0.90 x-------> (<span>is 10% percent less than the length of a side of square)
</span>[longer side]=1.10x-------> (<span>is 10% percent more than the length of a side of square
</span>
[area of rectangle]=(1.10x)*(0.90x)-----> 0.99x²

[the ratio of the area of rectangle to the area of square]=0.99x²/x²=0.99

the answer is
the ratio of the area of rectangle to the area of square is 0.99
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