The length of the longer side of rectangle $r$ is $10$ percent more than the length of a side of square $s.$ the length of the s
horter side of rectangle $r$ is $10$ percent less than the length of a side of square $s.$ what is the ratio of the area of rectangle $r$ to the area of square $s?$ express your answer as a common fraction.
Let x-------------> length of the side of a square
[area of a square]=x*x------> x²
[area of rectangle]=[shorter side]*[<span>longer side] </span>[shorter side]=0.90 x-------> (<span>is 10% percent less than the length of a side of square) </span>[longer side]=1.10x-------> (<span>is 10% percent more than the length of a side of square </span> [area of rectangle]=(1.10x)*(0.90x)-----> 0.99x²
[the ratio of the area of rectangle to the area of square]=0.99x²/x²=0.99
the answer is the ratio of the area of rectangle to the area of square is 0.99
