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3 years ago

10

A computer downloaded 20 kilobytes of data in 4 seconds. If it downloads data at a constant speed, it can download ______ kiloby

tes of data in 15 seconds.

2 answers:

ss7ja [257]3 years ago

8 0

The computer can download 75 kilobytes of data in 15 seconds

denpristay [2]3 years ago

3 0

It can download 75 kilobytes of data.

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Find the sum of the first 50 odd numbers

Svet_ta [14]

It’s 2500 because I solved it I just need to do 25*100 so I hope it’s right

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4 years ago

Find the solution of 2/3x+1/4=-4/3

wolverine [178]

These questions can be daunting at first, but they're pretty simple to solve.

First, we need to establish a common denominator. We have 2 / 3, 1 / 4, and
-4 / 3. The least common denominator we can get is by multiplying 4 and 3 together to get 12. So we will change the denominator as follows;

2 / 3, 1 / 4, -4 / 3 = 8 / 12, 3 / 12, -16 / 12

Now we can put these back into the equation.

8/12x + 3/12 = -16/12
8x + 3 = -16

It's simple math from here on out, but I'll show the process. What we can basically do now is take away the denominator because it doesn't matter now that it's common.

Subtract 3 from both sides. Now we have 8x = -19

Dividing by 8 on both sides of the equation will get you your answer.

x = -19/8

Hope this helps!

6 0

4 years ago

For the purpose of determining the value of its end-of-year inventory, a clothing store creates a list at the end of the year of

weeeeeb [17]

Answer:

e. A census, because the wholesale prices of all items are listed.

Step-by-step explanation:

A census encompasses collecting data of an entire population as well evaluation of the characteristics of an entire population. Every item currently in store alongside their wholesale price was included in the survey here. None was excluded. So we cannot call the activity a sample survey. Since all items were counted, the best description to give to this activity is "a census".

3 0

3 years ago

Assume that a randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of

jarptica [38.1K]

Answer:

The "probability that a given score is less than negative 0.84" is $\\ P(z$ .

Step-by-step explanation:

From the question, we have:

The random variable is <em>normally distributed</em> according to a <em>standard normal distribution</em>, that is, a normal distribution with $\\ \mu = 0$ and $\\ \sigma = 1$ .
We are provided with a <em>z-score</em> of -0.84 or $\\ z = -0.84$ .

Preliminaries

A z-score is a standardized value, i.e., one that we can obtain using the next formula:

$\\ z = \frac{x - \mu}{\sigma}$ [1]

Where

<em>x</em> is the <em>raw value</em> coming from a normal distribution that we want to standardize.
And we already know that $\\ \mu$ and $\\ \sigma$ are the mean and the standard deviation, respectively, of the <em>normal distribution</em>.

A <em>z-score</em> represents the <em>distance</em> from $\\ \mu$ in <em>standard deviations</em> units. When the value for z is <em>negative</em>, it "tells us" that the raw score is <em>below</em> $\\ \mu$ . Conversely, when the z-score is <em>positive</em>, the standardized raw score, <em>x</em>, is <em>above</em> the mean, $\\ \mu$ .

Solving the question

We already know that $\\ z = -0.84$ or that the standardized value for a raw score, <em>x</em>, is <em>below</em> $\\ \mu$ in <em>0.84 standard deviations</em>.

The values for probabilities of the <em>standard normal distribution</em> are tabulated in the <em>standard normal table, </em>which is available in Statistics books or on the Internet and is generally in <em>cumulative probabilities</em> from <em>negative infinity</em>, - $\\ \infty$ , to the z-score of interest.

Well, to solve the question, we need to consult the <em>standard normal table </em>for $\\ z = -0.84$ . For this:

Find the <em>cumulative standard normal table.</em>
In the first column of the table, use -0.8 as an entry.
Then, using the first row of the table, find -0.04 (which determines the second decimal place for the z-score.)
The intersection of these two numbers "gives us" the cumulative probability for z or $\\ P(z$ .

Therefore, we obtain $\\ P(z$ for this z-score, or a slightly more than 20% (20.045%) for the "probability that a given score is less than negative 0.84".

This represent the area under the <em>standard normal distribution</em>, $\\ N(0,1)$ , at the <em>left</em> of <em>z = -0.84</em>.

To "draw a sketch of the region", we need to draw a normal distribution <em>(symmetrical bell-shaped distribution)</em>, with mean that equals 0 at the middle of the distribution, $\\ \mu = 0$ , and a standard deviation that equals 1, $\\ \sigma = 1$ .

Then, divide the abscissas axis (horizontal axis) into <em>equal parts</em> of <em>one standard deviation</em> from the mean to the left (negative z-scores), and from the mean to the right (positive z-scores).

Find the place where z = -0.84 (i.e, below the mean and near to negative one standard deviation, $\\ -\sigma$ , from it). All the area to the left of this value must be shaded because it represents $\\ P(z$ and that is it.

The below graph shows the shaded area (in blue) for $\\ P(z$ for $\\ N(0,1)$ .

7 0

3 years ago

Reese wants to organize a party and decides to save money for it.He calculates that he needs $420 in 9 weeks.He already has $60

disa [49]

Answer:

3840

Step-by-step explanation:

5 0

3 years ago