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2 years ago

15

Identify the minimum or maximum value and the domain and range of the function

1 answer:

sdas [7]2 years ago

6 0

Y = 2 ( X - 3 ) ^ 2 - 4 =-4

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Juan adds 3.8+4.7 and gets a sum of 84 .Is his answer correct.tell how you know

Ivan

Answer:

His answer was wrong the answer should be 8.5 .

Step-by-step explanation:

3.8+4.7=8.5

3 0

2 years ago

Susan has 50% more books than Michael. Michael has 40 books. If Michael buys 8 more books, will Susan have more or less books th

ololo11 [35]

Answer:

Susan has more books than Michael.

Step-by-step explanation:

If Susan has 50% more books and Michael has 40 books, that means Susan has 1.5 times 40 = 60

40 + 8 = 48

60 is more than 48, so Susan has more books than Michael

7 0

2 years ago

John's commute time to work during the week follows the normal probability distribution with a mean time of 26.7 minutes and a s

Galina-37 [17]

A suitable probability calculator will tell you that probabilty is about 25.9%.

_____

The normalcdf function on this calculator gives an area between a lower and upper limit. If the upper limit is more than about 8 standard deviations above the mean, the 10th decimal place is unaffected. Since the standard deviation here is about 5, we need to have an upper limit that is about 40 above the mean of about 30. We have chosen 80 as a nice round number and to give a little more margin.

4 0

3 years ago

Find the accumulated value of an investment of $20,000 for 7 years at an interest rate of 5.5% if the money is:

Amiraneli [1.4K]

Answer:

See below

Step-by-step explanation:

<u>Given:</u>

Investment P = $20000
Time t = 7 years
Interest rate r = 5.5% = 0.055

a. <u>compounded semiannually, n = 2</u>

$A = P*(1 + r/n)^{nt} = 20000(1+0.055/2)^{2*7} = 29239.88$

b. <u>compounded quarterly, n = 4</u>

$A = P*(1 + r/n)^{nt} = 20000(1+0.055/4)^{4*7} = 29315.30$

c. <u>compounded monthly, n = 12</u>

$A = P*(1 + r/n)^{nt} = 20000(1+0.055/12)^{12*7} = 29366.44$

d. <u>compounded continuously</u>

$A = Pe^{rt}=20000*e^{0.055*7}=29392.29$

5 0

2 years ago

Read 2 more answers

The sequence$$1,2,1,2,2,1,2,2,2,1,2,2,2,2,1,2,2,2,2,2,1,2,\dots$$consists of $1$'s separated by blocks of $2$'s with $n$ $2$'s i

kicyunya [14]

Consider the lengths of consecutive 1-2 blocks.

block 1 - 1, 2 - length 2

block 2 - 1, 2, 2 - length 3

block 3 - 1, 2, 2, 2 - length 4

block 4 - 1, 2, 2, 2, 2 - length 5

and so on.

Recall the formula for the sum of consecutive positive integers,

$\displaystyle \sum_{i=1}^j i = 1 + 2 + 3 + \cdots + j = \frac{j(j+1)}2 \implies \sum_{i=2}^j = \frac{j(j+1) - 2}2$

Now,

$1234 = \dfrac{j(j+1)-2}2 \implies 2470 = j(j+1) \implies j\approx49.2016$

which means that the 1234th term in the sequence occurs somewhere about 1/5 of the way through the 49th 1-2 block.

In the first 48 blocks, the sequence contains 48 copies of 1 and 1 + 2 + 3 + ... + 47 copies of 2, hence they make up a total of

$\displaystyle \sum_{i=1}^48 1 + \sum_{i=1}^{48} i = 48+\frac{48(48+1)}2 = 1224$

numbers, and their sum is

$\displaystyle \sum_{i=1}^{48} 1 + \sum_{i=1}^{48} 2i = 48 + 48(48+1) = 48\times50 = 2400$

This leaves us with the contribution of the first 10 terms in the 49th block, which consist of one 1 and nine 2s with a sum of $1+9\times2=19$ .

So, the sum of the first 1234 terms in the sequence is 2419.

8 0

1 year ago