Answer:
A t-score of 2.0244 should be used to find the 99% confidence interval for the population mean
Step-by-step explanation:
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 39 - 1 = 38
Now, we have to find a value of T, which is found looking at the t table, with 38 degrees of freedom(y-axis) and a confidence level of 0.99(
). So we have T = 2.0244.
A t-score of 2.0244 should be used to find the 99% confidence interval for the population mean
2[5+2(8-6)]
2[5+2(2)]
2[5+4]
2[9]
18
All you have to do is divide each one by its other number. For example, 5.60 for 8 is the same as one for 0.70. We accomplish this by dividing the 5.60 by 8.
So...
0.70
0.80
0.90
0.75
The first choice is the lowest.
To get it into standard you need to simplify
6y - 12 = -3x add 12 to both sides
6y = -3x + 12 add 3x to both sides
3x + 6y = 12
And that is in standard which is A + B = C
Ohh come se diceee uhhh i dont know the answer :)