Answer: 
We have something in the form log(x/y) where x = q^2*sqrt(m) and y = n^3. The log is base 2.
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Explanation:
It seems strange how the first two logs you wrote are base 2, but the third one is not. I'll assume that you meant to say it's also base 2. Because base 2 is fundamental to computing, logs of this nature are often referred to as binary logarithms.
I'm going to use these three log rules, which apply to any base.
- log(A) + log(B) = log(A*B)
- log(A) - log(B) = log(A/B)
- B*log(A) = log(A^B)
From there, we can then say the following:

The answer is 5 I’m not sure if this is correct
A.) 14/15 B.) 17/14 C.) 5/12
The common denominator for 25 and 20 would be 100
25 x 4 = 100
20 x 5 = 100
Rewrite 14/25 as 14 x 4 / 25 x 4 = 56/100
Rewrite 11/20 as 11 x 5 / 20 x 5 = 55/100
14/25 is greater than 11/20
14/25 > 11/20