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agasfer [191]
3 years ago
12

1. Find the mean, median, mode, and range of the number of chapters per book of the Old Testament. Be sure to show how you arriv

ed at your answers. 2. Find the 5 number summary for the number of chapters in the Old Testament. (Recall that the 5-number summary is the minimum, lower quartile, median, upper quartile, and maximum.) Be sure to show how you arrived at your answers. 3. Use your 5-number summary from question #2 to draw a box-and-whisker plot for your data. (Be sure that your number line has a consistent scale so it isn’t misleading.) 4. Create a histogram to display the disbursement of the number of chapters in the books of the Old Testament. Use a scale of 1-20, 21-40, 41-60, 61-80, and so on. 5. Write a paragraph that answers the following questions: a. Were there any outliers in the data? If so, what were they and what do they do to the data? b. Which measure of central tendency do you feel most accurately describes the data? Be sure to validate your choice. c. If you were explaining to a friend how many chapters were, on average, in a book of the Old Testament, what would you tell him? Why? (Use data from your answers above to support your explanation.) d. Did any data in this project stand out to you? Why or why not? Book: Number of Chapters: Book: Number of Chapters: Book: Number of Chapters: Genesis 50 2 Chronicles 36 Daniel 12 Exodus 40 Ezra 10 Hosea 14 Leviticus 27 Nehemiah 13 Joel 3 Numbers 36 Esther 10 Amos 9 Deuteronomy 34 Job 42 Obadiah 1 Joshua 24 Psalms 150 Jonah 4 Judges 21 Proverbs 31 Micah 7 Ruth 4 Ecclesiastes 12 Nahum 3 1 Samuel 31 Song of Solomon 8 Habakkuk 3 2 Samuel 24 Isaiah 66 Zephaniah 3 1 Kings 22 Jeremiah 52 Haggai 2 2 Kings 25 Lamentations 5 Zechariah 14 1 Chronicles 29 Ezekiel 48 Malachi 4
Mathematics
1 answer:
Savatey [412]3 years ago
7 0

Answer:

dude plz send a picture

Step-by-step explanation: this is confusing

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Engineers want to design seats in commercial aircraft so that they are wide enough to fit 90​% of all males.​ (Accommodating 100
gladu [14]

Answer:

  16.053 inches

Step-by-step explanation:

Many such probability questions are easily answered by a suitable calculator or spreadsheet.

4 0
3 years ago
Select the correct answer from each drop-down menu.
navik [9.2K]

Answer:

(0,1/5) and (1/9,0)

Step-by-step explanation:

3/5x +1/3y=1/15

To find intercepts, plug in 0

y-intercept: 3/5(0) + 1/3y=1/15

y=1/15*3 = 3/15 = 1/5 or 0.2

x-intercept: 3/5x + 1/3(0) = 1/15

3x=1/15*5/3

x=5/45= 1/9

3 0
3 years ago
A water tank is in the shape of a cone.Its diameter is 50 meter and slant edge is also 50 meter.How much water it can store In i
Aneli [31]
To get the most accurate answer possible, we're going to have to go into some unsightly calculation, but bear with me here:

Assessing the situation:

Let's get a feel for the shape of the problem here: what step should we be aiming to get to by the end? We want to find out how long it will take, in minutes, for the tank to drain completely, given a drainage rate of 400 L/s. Let's name a few key variables we'll need to keep track of here:

V - the storage volume of our tank (in liters)
t - the amount of time it will take for the tank to drain (in minutes)

We're about ready to set up an expression using those variables, but first, we should address a subtlety: the question provides us with the drainage rate in liters per second. We want the answer expressed in liters per minute, so we'll have to make that conversion beforehand. Since one second is 1/60 of a minute, a drainage rate of 400 L/s becomes 400 · 60 = 24,000 L/min.

From here, we can set up our expression. We want to find out when the tank is completely drained - when the water volume is equal to 0. If we assume that it starts full with a water volume of V L, and we know that 24,000 L is drained - or subtracted - from that volume every minute, we can model our problem with the equation

V-24000t=0

To isolate t, we can take the following steps:

V-24000t=0\\ V=24000t\\ \frac{V}{24000}=t

So, all we need to do now to find t is find V. As it turns out, this is a pretty tall order. Let's begin:

Solving for V:

About units: all of our measurements for the cone-shaped tank have been provided for us in meters, which means that our calculations will produce a value for the volume in cubic meters. This is a problem, since our drainage rate is given to us in liters per second. To account for this, we should find the conversion rate between cubic meters and liters so we can use it to convert at the end.

It turns out that 1 cubic meter is equal to 1000 liters, which means that we'll need to multiply our result by 1000 to switch them to the correct units.

Down to business: We begin with the formula for the area of a cone,

V= \frac{1}{3}\pi r^2h

which is to say, 1/3 multiplied by the area of the circular base and the height of the cone. We don't know h yet, but we are given the diameter of the base: 50 m. To find the radius r, we divide that diameter in half to obtain r = 50/2 = 25 m. All that's left now is to find the height.

To find that, we'll use another piece of information we've been given: a slant edge of 50 m. Together with the height and the radius of the cone, we have a right triangle, with the slant edge as the hypotenuse and the height and radius as legs. Since we've been given the slant edge (50 m) and the radius (25 m), we can use the Pythagorean Theorem to solve for the height h:

h^2+25^2=50^2\\ h^2+625=2500\\ h^2=1875\\ h=\sqrt{1875}=\sqrt{625\cdot3}=25\sqrt{3}

With h=25\sqrt{3} and r=25, we're ready to solve for V:

V= \frac{1}{3} \pi(25)^2\cdot25\sqrt{3}\\ V= \frac{1}{3} \pi\cdot625\cdot25\sqrt{3}\\ V= \frac{1}{3} \pi\cdot15625\sqrt{3}\\\\ V= \frac{15625\sqrt{3}\pi}{3}

This gives us our volume in cubic meters. To convert it to liters, we multiply this monstrosity by 1000 to obtain:

\frac{15625\sqrt{3}\pi}{3}\cdot1000= \frac{15625000\sqrt{3}\pi}{3}

We're almost there.

Bringing it home:

Remember that formula for t we derived at the beginning? Let's revisit that. The number of minutes t that it will take for this tank to drain completely is:

t= \frac{V}{24000}

We have our V now, so let's do this:

t= \frac{\frac{15625000\sqrt{3}\pi}{3}}{24000} \\ t= \frac{15625000\sqrt{3}\pi}{3}\cdot \frac{1}{24000} \\ t=\frac{15625000\sqrt{3}\pi}{3\cdot24000}\\ t=\frac{15625\sqrt{3}\pi}{3\cdot24}\\ t=\frac{15625\sqrt{3}\pi}{72}\\ t\approx1180.86

So, it will take approximately 1180.86 minutes to completely drain the tank, which can hold approximately V= \frac{15625000\sqrt{3}\pi}{3}\approx 28340615.06 L of fluid.
5 0
3 years ago
The roots of the equation (blank) are x=2+-i.
professor190 [17]
The answer is x^2-4x+5=0
8 0
3 years ago
An apple orchard sells apples in bags of 10.the orchard sold a total of 2,430 apples one day.how many bags of apples waa
Kruka [31]
243 bags of apples were sold in one day 
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