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3 years ago

What is the surface area of the rectangular pyramid below

Mathematics

2 answers:

Kobotan [32]3 years ago

6 0

$S=15\times15+4(7.5\times15)=\boxed{675}$

Mademuasel [1]3 years ago

5 0

Answer:

Option C is correct.

Step-by-step explanation:

Given:

Length of the base rectangle = 15 unit

Width of the base rectangle = 15 unit

Height of triangle on the side of pyramid = 15 unit

Length of the base of the triangle = 15 unit

Surface are of the rectangular pyramid = Area of Base + 4 × Area of triangle on side.

Area of base = length × width = 15 × 15 = 225 unit²

Area of the triangle = 1/2 × base × height = 1/2 × 15 × 15 = 112.5 unit²

Surface Area = 225 + 4 × 112.5 = 225 + 450 = 675 unit²

Therefore, Option C is correct.

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The gestation period of humans (266 days) is what percent longer than the gestation period of pigs (115 days).

ruslelena [56]

Answer:

56.8%

Step-by-step explanation:

(115/266)* 100 = 43.2%

which means 115 is 43.2% of 266

so,

The gestation period for Humans is 56.8% (100 - 43.2) longer than of pigs

I hope this is correct!

7 0

3 years ago

can someone help me solve this question

kodGreya [7K]

Answer:

Step-by-step explanation:

y=mx+b

m = slope

b = y intercept

m = 5

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4 0

3 years ago

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Solve. + Х ) = - 1/2 + ( 3/4 x 4/9)

gregori [183]

Steps to solve:

-1/2 + (3/4 * 4/9)

~Simplify

-1/2 + 14/36

~Simplify

-1/2 + 7/18

~Find common denominators

-9/18 + 7/18

~Add

-2/18 or -1/9

Best of Luck!

5 0

3 years ago

Read 2 more answers

2=m/2-7 M/2 is a fraction btw

ad-work [718]

Answer:

18 = m

Step-by-step explanation:

2=m/2-7

Add 7 to each side

2+7=m/2 - 7+7

9 = m/2

Multiply each side by 2

9*2 = m/2 * 2

18 = m

7 0

2 years ago

Objects A and B are in harmonic motion modeled by

Zepler [3.9K]

Answer:

The phase difference between yA and yB is $\frac{-\pi }{12}$

Step-by-step explanation:

Given harmonic modeled as :

yA = 8 sin(2t - $\frac{\pi }{3}$ ) And

yB = 8 sin(2t - $\frac{\pi }{4}$ )

The function as written as :

y = a sin(ωt - Ф) where Ф is phase difference

So , phase difference between yA and yB = ( Ф_1 - Ф_2 )

Or phase difference between yA and yB = ( - $\frac{\pi }{3}$ + $\frac{\pi }{4}$ )

Or, phase difference between yA and yB = $(\frac{-4\pi +3\pi }{12})$

I.e phase difference between yA and yB = $\frac{-\pi }{12}$

Hence The phase difference between yA and yB is $\frac{-\pi }{12}$ Answer

4 0

3 years ago

Read 2 more answers