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nika2105 [10]
3 years ago
10

The director of health services is concerned about a possible flu outbreak at her college.

Mathematics
2 answers:
Mekhanik [1.2K]3 years ago
8 0

Answer: The accurate answer is 13/17.

Step-by-step explanation:

Anna [14]3 years ago
5 0
"Given that he is male" is an important phrase here. The "given" in any probability problem is often important. This tells us "only focus on the males" because we know 100% that whoever we picked, the person is a male. 

So we only focus on the "male" column. Use a highlighter to mark this column or cover up the other values if they are too distracting. There are 51 males total (bottom row) and 39 males had a flu shot (top row)

Divide the two values: 39/51 = (13*3)/(17*3) = 13/17

Answer: 13/17
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Someone please help me answer this!!!
sashaice [31]

Answer:

4.8 km is the answer.

Step-by-step explanation:

a = ?

b = 5 km

c = 7 km

According to the Pythagorean theorem,

a² + b² = c²

a² + 5² = 7²

a² + 25 = 49

a² = 49 - 25

a² = 24

a = 4.8989

Round to the nearest tenth,

a = 4.8 km

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Find an explicit rule for the nth term of the sequence.The second and fifth terms of a geometric sequence are 18 and 144, respec
vova2212 [387]

Given:

second term = 18

fifth term = 144

The nth term of a geometric sequence is:

\begin{gathered} a_n\text{ = ar}^{n-1} \\ Where\text{ a is the first term} \\ r\text{ is the common ratio} \end{gathered}

Hence, we have:

\begin{gathered} \text{ar}^{2-1}\text{ = 18} \\ ar\text{ = 18} \\  \\ ar^{5-1}=\text{ 144} \\ ar^4\text{ =144} \end{gathered}

Divide the expression for the fifth term by the expression for the second term:

\begin{gathered} \frac{ar^4}{ar}\text{ = }\frac{144}{18} \\ r^3\text{ = }\frac{144}{18} \\ r\text{ = 2} \end{gathered}

Substituting the value of r into any of the expression:

\begin{gathered} ar\text{ =  18} \\ a\text{ }\times\text{ 2 =  18} \\ Divide\text{ both sides by 2} \\ \frac{2a}{2}\text{ =}\frac{18}{2} \\ a\text{ = 9} \end{gathered}

Hence, the explicit rule for the sequence is:

a_n\text{ = 9\lparen2\rparen}^{n-1}

5 0
1 year ago
1+sin^2 x = 2-cos^2 x
Alinara [238K]
1+sin²x=2-cos²x
Remenber:   sin²x+cos²x=1      ⇒sin²x=1-cos²x
 
1+sin²x=1+(1-cos²x)=2-cos² x       (this is true)

3 0
2 years ago
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