Answer:
y = (3/5)x+26/5 or 5y = 3x+26
Step-by-step explanation:
Applying,
The equation of a line in two point form
(y₂-y₁)/(x₂-x₁) = (y-y₁)/(x-x₁)............... Equation 1
From the question,
Given: y₂ = 7, y₁ = 4, x₂ = 3, x₁ = -2
Substitute these values into equation 1
(7-4)/[3-(-2)] = (y-4)/(x+2)
3/5 = (y-4)/(x+2)
5(y-4) = 3(x+2)
5y-20 = 3x+6
5y = 3x+6+20
5y = 3x+26
y = (3/5)x+26/5
Hence the equation of the line is y = (3/5)x+26/5 or 5y = 3x+26
9k2-12k+4
(k2-6k)+(-6k+4) factor out the 3k from 9k2 0 6k: 3k(k-2) factor out -2 from -6k +4n: -2 (3k-2) factor out common term (3k-2) = (3k-2 ) (3k-2) that equals (3k-2)2
AP and BQ are medians of the triangle ABC and K is the centroid of the triangle.
One of the properties of the medians is that the point of intersection divides the median in the ratio 2:1
So BK = 2 KQ therefore
15 = 2 * KQ
and KQ = 7.5 answer
Answer:
-15804
Step-by-step explanation:
Answer:
84
Step-by-step explanation:
Given a quadratic equation in standard form, ax² + bx + c = 0 : a ≠ 0
Then the discriminant is Δ = b² - 4ac
2k² = 10k - 2 ( subtract 10k - 2 from both sides )
2k² - 10k + 2 = 0 ← in standard form
with a = 2, b = - 10 and c = 2, thus
b² - 4ac = (- 10)² - (4 × 2 × 2) = 100 - 16 = 84
