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Zepler [3.9K]
3 years ago
6

3. + 4(4x - 3) = 4(6x + 4) +4

Mathematics
2 answers:
allsm [11]3 years ago
6 0

Answer: -4

Step-by-step explanation:

VMariaS [17]3 years ago
5 0

Answer:

x= -29/8 or -3.625

Step-by-step explanation:

that is the answer

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Write the equation of a line that is perpendicular to y=5 and that passes through the point (−7,−5)
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x =  - 7 \\  \\ hope \: it \: helps

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one vertex of a triangle is located at (0,5) on a coordinate grid after a transformation the vertex is located at(5,0) which tra
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Answer:

It's a rotation clockwise of 90 degrees about the origin.

Step-by-step explanation:

The given point moves from   y = 5 to x = 5 so it has passed through 90 degrees about the origin.

It's a rotation clockwise of 90 degrees about the origin.

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3 years ago
PLZ HELP!
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Answer:

The area of the triangle is 36 square units

Step-by-step explanation:

First you can make the graph to set up the problem. You then plot the point 3,6 (A). You then reflect this over the Y axis which would be the point -3,6 (B). Point A is then reflected over the X axis to give you 3,-6 (C). You then multiply their total lengths 12 and 6 which is 72. Then you divide 72 by 2 because it is a triangle to get 36

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san4es73 [151]
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6 0
3 years ago
In the expansion (ax+by)^7, the coefficients of the first two terms are 128 and -224, respectively. Find the values of a and b
madam [21]

Answer:

a = 2, b = 3.5

Step-by-step explanation:

Expanding (ax+by)^7 using Binomial expansion, we have that:

(ax+by)^7 =

(ax)^7(by)^0 + (ax)^6(by)^1 + (ax)^5(by)^2 + (ax)^4(by)^3 + (ax)^3(by)^4 + (ax)^2(by)^5 + (ax)^1(by)^6 + (ax)^0(by)^7

= (a)^7(x)^7+ (a)^6(x)^6(b)(y) + (a)^5(x)^5(b)^2(y)^2 + (a)^4(x)^4(b)^3(y)^3 + (a)^3(x)^3(b)^4(y)^4 + (a)^2(x)^2(b)^5(y)^5 + (a)(x)(b)^6(y)^6 + (b)^7(y)^7\\\\\\= (a)^7(x)^7+ (a)^6(b)(x)^6(y) + (a)^5(b)^2(x)^5(y)^2 + (a)^4(b)^3(x)^4(y)^3 + (a)^3(b)^4(x)^3(y)^4 + (a)^2(b)^5(x)^2(y)^5 + (a)(b)^6(x)(y)^6 + (b)^7(y)^7

We have that the coefficients of the first two terms are 128 and -224.

For the first term:

=> a^7 = 128

=> a = \sqrt[7]{128}\\ \\\\a = 2

For the second term:

a^6b = -224

b = \frac{-224}{a^6}

b = \frac{-224}{2^6} \\\\\\b = \frac{-224}{64} \\\\\\b = 3.5

Therefore, a = 2, b = 3.5

5 0
2 years ago
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