All categories

3 years ago

A container is 24m long ,9m wide and 8m high.how many books can it holds if eachbook is 20cm long,16cm wide and 6cm thick

1 answer:

6 0

Assuming that the container and books are rectangular, the volume of both objects can be computed with the formula V=lwh, where l is length, w is width, and h is height.
As the volume of the container is 1728 m^3, while the volume of each book is 1920 cm^3. The volume for each book is converted to in terms of meters by dividing it with 100^3. The volume for each book after this conversion is 1.92 x 10^-3 m^3.
The number of the books that can fit in the shelf is the volume of the shelf divided by the volume of the books, with the assumption that the books fit perfectly in the shelf.
With the volume of the shelf divided by the volume of the books, 900,000 books can be fitted in the shelf.

You might be interested in

Kittens weigh about 100 grams when born and gain 7 to 15 grams per day.If a kitten weighed 100 grams at birth and gained 8 grams

natka813 [3]

100 + 8d = 300; d = 25; The kitten will triple its weight in 25 days

8 0

3 years ago

Read 2 more answers

1. Carter will install fencing all around the flat area of his

MariettaO [177]

Answer:

Amount of fencing required = 75 yards

Step-by-step explanation:

Distance between the two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by the formula,

d = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Distance between A(3, 6) and B(3, -2) = $\sqrt{(3-3)^2+(6+2)^2}$

= 8 yards

Distance between B(3, -2) and C(-7, 4) = $\sqrt{(3+7)^2+(-2-4)^2}$

= $\sqrt{136}$

= 11.66 ≈ 12 yards

Distance between C(-7, 4) and D(-7, -2) = $\sqrt{(-7+7)^2+(4+2)^2}$

= 6 yards

Distance between D(-7, -2) and E(-3, -2) = $\sqrt{(-7+3)^2+(-2+2)^2}$

= 4 yards

Distance between E(-3, -2) and F(-3, -8) = $\sqrt{(-3+3)^2+(-2+8)^2}$

= 6 yards

Distance between F(-3, -8) and G(3, -8) = $\sqrt{(-3-3)^2+(-8+8)^2}$

= 6 yards

Distance between G(3, -8) and H(10, -12) = $\sqrt{(3-10)^2+(-8+12)^2}$

= $\sqrt{49+16}$

= $\sqrt{65}$

= 8.06 ≈ 8 yards

Distance between H(10, -12) and J(10, 6) = $\sqrt{(10-10)^2+(-12-6)^2}$

= 18 yards

Distance between A(3, 6) and J(10, 6) = $\sqrt{(10-3)^2+(6-6)^2}$

= 7 yards

Since length of fence required = perimeter of the flat area

Perimeter of the given area = 8 + 12 + 6 + 4 + 6 + 6 + 8 + 18 + 7

= 75 yards

Therefore, amount of fencing required = 75 yards

8 0

3 years ago

Estimate 34,182-18,717 by first rounding each number to the nearest thousand.

tresset_1 [31]

Answer:

15,000

Step-by-step explanation:

First, round both the numbers:

34,182 rounds down to 34,000

18,717 rounds up to 19,000

Subtract you're two rounded numbers

34,000 - 19,000 = 15,000

6 0

3 years ago

Please help I beg like right now and explain peae

Lyrx [107]

Answer and Step-by-step explanation:

When we take a look at the graph, we can see that at around 1 gallon, which would be halfway between 0 and 2, the line is underneath $5.

That means we can eliminate any number that is or above $5.

That leaves us with answer choices A and C.

Let's go to a point that is easily readable. Point (4, 15) is readable, and we can use this to find the price per gallon.

Divide 15 by 4. We get 3.75 as the result.

This means that the answer choice is:

C. The cost of gas is $3.75 per gallon.

#teamtrees #PAW (Plant And Water)

6 0

3 years ago

Gisselle has 1/2 of a candy bar. She role off 1/2 of what she had. She then took the piece she broke off and split it into three

saul85 [17]

Answer:

$\frac{1}{12}$

Step-by-step explanation:

Given:

Gisselle has 1/2 of a candy bar.

She role off 1/2 of what she had and split it into three equal pieces.

Question asked:

What fraction of a candy bar was each piece?

Solution:

Gisselle has = $\frac{1}{2} \ of \ a \ candy \ bar$

She role off = $\frac{1}{2} \ of \ what\ she \ had$

$=\frac{1}{2} \ of\ \frac{1}{2}\\=\frac{1}{2} \times \frac{1}{2}\\\\=\frac{1}{4}$

As she split it into three equal pieces, we will divided it by 3, we get,

$\frac{1}{4} \div3\\\frac{1}{4}\times\frac{1}{3}$

$\frac{1}{12}$

Therefore, fraction of a candy bar of each piece is $\frac{1}{12}$

4 0

3 years ago