If the standard deviation of an exam is 5, the z-score us 1.95 and the mean is 80, the actual test score is; 89.75
<h3>How to solve z-score problems?</h3>
We are given;
Standard deviation; s = 5
z-score = 1.95
Mean = 80
Formula for z-score is;
z = (x' - μ)/σ
Thus;
1.95 = (x' - 80)/5
1.95 * 5 = (x' - 80)
9.75 = x' - 80
x' = 80 + 9.75
x' = 89.75
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Answer:
Sarah's Store
Step-by-step explanation:
Answer:
125 defective jeans
Step-by-step explanation:
We are told that;
During inspections, 5 defective pairs of jeans are found in a shipment of 200 pairs of jeans .
We are supposed to determine the number of defective jeans in a shipment of 5000 pairs, if the trend continues.
Therefore;
5 defective = 200 pairs
What about in 5000 pairs?
Number of defective pairs = (5000 × 5 ) ÷ 200
= 125 defective pairs
Thus, in a shipment of 5000 pairs of jeans there will be 125 defective pairs
The second one because the denominator is smaller meaning the second term is smaller and the first is bigger 2/3 > 2/4
