The solution for the problem is:
I will first get the first five terms so that I could easily locate the third term of this problem:So, substituting the values:
T(1) = 1^2 = 1T(2) = 2^2 = 4T(3) = 3^2 = 9T(4) = 4^2 = 16T(5) = 5^2 =25
So the third terms is T(3) = 3^2 = 9
Answer:
let's use Pythagoras theorem,
h²=b²+l²
so,
ad²=ac²+dc²
6²=ac²+3²
36-9=ac²=27
√27 can be written as 3√3,
hence ac= 3√3
Answer:
Step-by-step explanation:
distribute 5 in parenthesis means you multipy each term by 5
5*1-5*2 g+5*4h = 5-10g+20h
Answer:
g(x)=0 when x= 2 or when x= 5
The graph of g intercepts the x-axis at x= 2 and x= 5
The zeros of g are 2 and 5
Step-by-step explanation:
