Sequence for the movement of electrons during the light dependent reaction
Explanation:
1.These reactions occur within specialised membrane discs within the chloroplast called thylakoids and involve three steps: Excitation of photosystems by light energy. Production of ATP via an electron transport chain. Reduction of NADP+ and the photolysis of water.
2.The cyclic light-dependent reactions occur only when the sole photosystem being used is photosystem I. Photosystem I excites electrons which then cycle from the transport protein, ferredoxin (Fd), to the cytochrome complex, b6f, to another transport protein, plastocyanin (Pc), and back to photosystem
3.Light-dependent reaction. In photosynthesis, the light-dependent reaction uses light energy from the sun to split water (photolysis). ... Water, when broken, makes oxygen, hydrogen, and electrons. These electrons move through structures in chloroplasts and by chemiosmosis, make ATP
4.The two products of the light-dependent reactions of photosystem are ATP and NADPH. The movement of high energy electrons releases the free energy that is needed to produce these molecules. The ATP and NADPH are used in the light-independent reactions to make sugar.
The answer is negative controls. These are groups where no phenomenon is probable. They ensure that there is no effect when there should be no effect. Where there are only two possible outcomes, e.g. positive or negative, if the treatment group and the negative control both produce a negative result, it can be concluded that the treatment had no effect. If the negative control group and the treatment group both yield a positive result, it can be inferred that a puzzling variable is involved in the occurrence under study, and the positive results are not only due to the treatment. In other examples, outcomes might be measured as lengths, times, percentages, and so forth.
Answer:
Ambot nimo hahahhahahahahhahaa
Answer: The given statement is true.
Explanation: Ionization energy is defined as the amount of energy required to remove an electron from the outermost shell of an isolated gaseous atom.
General equation of ionization energy is given by:
- If the outermost electron is loosely bound to the nucleus which means that the electron can be easily removed form an atom, it will require less amount of ionization energy.
- And if the outermost electron is tightly bound to the nucleus which means that the electron cannot be removed easily from an atom. And hence, it will require more ionization energy.
Hence, the given statement is true.
