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lara31 [8.8K]
3 years ago
13

Unsaturated fats have ____________ as a part of their structure. these bonds are generally in the ____________ in naturally occu

rring fats
Biology
1 answer:
kodGreya [7K]3 years ago
8 0
Unsaturated fats have at least one double bond as a part of their structure. These bonds are generally in the cis-conformation in naturally occurring fats.
<span>
In the cis conformation, H atoms are on the same side of the double bond, whereas in the trans conformation, they are on opposite sides of the double bond.</span>
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Assume that one of the disinfectant/antiseptics tested using the disc method had a clear zone of inhibition and to your surprise
o-na [289]

The presence of the minute growth near the disc signifies that the bacterial innoculum contains mutant microorganisms that are able to grow in the presence of toxic substances.

<h3>What are zones of inhibition?</h3>

The sensitivity testing in a microbiology laboratory is done to determine the effect of antibiotics on various bacteria organisms

The zone of inhibition when a disk method is used signifies the area of media where bacteria are unable to grow, due to presence of a drug that impedes their growth.

If there are presence of minute growth near the disc, it means that the bacterial innoculum contains mutant microorganisms that are able to grow in the presence of toxic substances such as disinfectants.

If these mutant bacteria organisms are not cleared by the disk method, it means that they cannot be killed by the disinfectant/antiseptics that is being tested.

Learn more about antiseptics here:

brainly.com/question/26994900

8 0
2 years ago
2. Dominant trait: cleft chin (C) Mother’s gametes: Cc
andre [41]

.2. Offspring Genotypes will be Cc or cc.

     Offspring phenotypes : Cleft chin or no cleft chin.

    % chance child will have cleft chin: 50%

3.  % chance child will have arched feet: 25%

4.  % chance child will have blonde hair:  50%

5.  % chance child will have normal vision: 25%

 

Explanation:

CASE 1 :

 Dominant trait: cleft chin (C)

    Recessive trait: lacks cleft chin (c)

    Father’s gametes: cc

    Mother’s gametes: Cc

There are two possible combination of Gametes ,

C fom mother and  c from father= Cc

c from mother and c from father = cc

Gametes of Cc Parents=  \frac{1}{2}C + \frac{1}{2} c........(i)

Gametes of cc parents =<u> </u>\frac{1}{2}c + \frac{1}{2}c .........(ii)

Combining (i) and (ii) we get,

\frac{1}{2}  Cc + \frac{1}{2} cc                              

There fore offspring Genotypes will be Cc or cc

Offspring phenotypes :

Genotype Cc then phenotype= Cleft chin

Genotype cc then phenotype = Lacks cleft chin.

percentage chance child will have cleft chin  =\frac{0.5}{1} ×100

Therefore the chance is 50%.

CASE 2 :

Dominant trait: flat feet (A)

Recessive trait: arched feet (a)

Mother’s gametes: Heterozygous (Aa)

Father’s gametes: Heterozygous   (Aa)

There are four possible combination of genotypes are =AA , Aa, Aa and aa

i.e. A from mother, A from father= AA

     A from mother, a from father =Aa

     a from mother, A from Father = Aa

     a from mother, a from father = aa

Gametes of Aa parent =\frac{1}{2} A + \frac{1}{2} a

Gametes of other Aa parent = \frac{1}{2} A + \frac{1}{2} a

                                       <u>..................................................................................</u>

                                              \frac{1}{4} AA + \frac{1}{4} Aa

                                                                           +  \frac{1}{4} Aa +\frac{1}{4} aa

                                   <u>..........................................................................................</u>

                                <u>\frac{1}{4}AA + \frac{1}{2}Aa +\frac{1}{4} aa</u>

Offspring Genotypes will be: AA or Aa or aa

Offsprings phenotype will be:

Genotype AA then phenotype will be Flat feet

Genotype Aa then phenotype will be flat feet

Genotype aa then Phenotype will be arched feet.

Percentage chance child will have arched feet = \frac{0.25}{1} × 100 = 25%

CASE 3:

Dominant trait: Brown hair (B)

Recessive trait: Blonde hair (b)

Mother’s gametes: Homozygous recessive  (bb)

Father’s gametes: Heterozygous  (Bb)

This case is very similar to the case 1 as one parent is homozygous recessive and other parent is heterozygous.

Resulting in  half  Bb and halve bb combination.

Genotypes will be Bb or bb

Phenotypes will be :

Genotype Bb then phenotype Brown hair

Phenotype bb then Phenotype bb.

% chance child will have blonde hair: 50%

CASE 4:

Dominant trait: farsightedness (F)

Recessive trait: normal vision (f)

Mother’s gametes: Heterozygous  (Ff)

Father’s gametes: Heterozygous  (Ff)

This Case is similar to case 2

it will result in one-fourth FF , half Ff and one-fouth ff combination.

Therefore Genotypes will be: FF, Ff and ff

Phenotypes:

Genotype FF  then phenotype farsightedness

Genotype Ff then phenotype  farsightedness

Genotype ff then phenotype normal vision.

% chance child will have normal vision: 25%

 

3 0
3 years ago
Which of the following factors would make the smallest contribution to determining the climate of an ecosystem?
sergiy2304 [10]

Answer:

Latitude. ...

Elevation. ...

Ocean Currents. ...

Topography. ...

Vegetation. ...

Prevailing winds.

5 0
2 years ago
Search BrainPOP
bagirrra123 [75]
A hypothesis is uneducated guess guess, or A guess you make before not knowing anything about the topic. The theory is A educated guess . Siri you would already know information about the topic and then putting your input
4 0
3 years ago
PLEASE HELP QUICK!!!!!! WILL GIVE BRAINIEST!!!!!!
tatyana61 [14]
It’s the second one I believe:)
5 0
3 years ago
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