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DanielleElmas [232]
3 years ago
15

Find the midpoint of the segment between (6,7) and (6,-5)

Mathematics
2 answers:
otez555 [7]3 years ago
8 0

Answer:

  • (6, 1)

Step-by-step explanation:

<h3>Given</h3>
  • Segment (6, 7) and (6, -5)
<h3>To find</h3>
  • Midpoint
<h3>Solution</h3>

x- coordinates same so the line is vertical and we'll only calculate the y-coordinate

  • x= 6
  • y = (7 + (-5))/2 = 2/2 = 1

<u>So the point is</u>

  • (6, 1)
Norma-Jean [14]3 years ago
3 0

Answer:

(6,1)

Step-by-step explanation:

midpoint = ((x2+x1),(y2+y1)/2)

= (6+6)/2, (-5+7)/2

= 12/2, 2/2

= 6,1

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FINDDD VALUE OF Y!!!!
solmaris [256]

Answer:

The sum of the internal ángles = 360°

(3y+40)°  and  (3x-70°) are suplementary angles = 180°

then:

(3x-70) + (3y+40) + 120 + x = 360     ⇒ first eq.

(3y+40) + (3x-70) = 180      ⇒  second eq

development:

from the first eq.

3x + x + 3y  =  360  + 70 - 40 - 120

4x + 3y = 430 - 160

4x + 3y = 270       ⇒  third eq.

3y = 270 - 4x

y = (270 - 4x) / 3    ⇒  fourth eq.

from the secon eq.:

3y + 3x = 180 + 70 - 40

3y + 3x = 250 - 40

3y + 3x = 210    ⇒  fifth eq.

multiply by -1  the fifth eq and sum with the third eq.

  -3y  - 3x = -210    ⇒   (fifth eq. *-1)

   3y  + 4x = 270

⇒  0   +  x  = 60

x = 60°

from the fourth eq.

y = (270-4x)/3

y = (270-(4*60)) / 3

y = (270 - 240) / 3

y = 30/3

y = 10°

Probe:

from the first eq.

(3x-70) + (3y+40) + 120 + x = 360

3*60 - 70 + 3*10 + 40 + 120 + 60 = 360

180 - 70 + 30 + 40 + 120 + 60 = 360

180 + 30 + 40 + 120 + 60 - 70 = 360

430 - 70 = 360

Answer:

y = 10

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