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zalisa [80]
3 years ago
15

The length of a rectangle is 8cm greater than twice its width. Find the dimensions if the area

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
7 0

Answer:

Length 14\ cm

Width 3\ cm

Step-by-step explanation:

Let

x-----> the length of rectangle

y ----> the width of rectangle

we know that

The area of rectangle is equal to

A=xy

A=42\ cm^{2}

so

42=xy ----> equation A

x=2y+8 ---> equation B

substitute equation B in equation A and solve for y

42=(2y+8)y\\ \\2y^{2}+8y-42=0

Solve the quadratic equation by graphing

The solution is y=3\ cm

see the attached figure

Find the value of x

x=2(3)+8=14\ cm

therefore

Length 14\ cm

Width 3\ cm

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