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3 years ago

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Which graph represents the function y – 3 = y minus 3 equals StartFraction 3 Over 2 EndFraction left-parenthesis x minus 4 right

-parenthesis.(x – 4)? A coordinate grid with a line passing through the points (0, negative 3) and (2, 0). A coordinate grid with a line passing through the points (negative 2, 0) and (0, negative 3). A coordinate grid with a line passing through the points (negative 4, negative 3) and (2, 1). A coordinate grid with a line passing through the points (negative 1, 1) and (1, 1).

2 answers:

UkoKoshka [18]3 years ago

6 0

Answer:

the answer is A

Step-by-step explanation:

:)

Deffense [45]3 years ago

3 0

Answer:

A line passing through the points (0, negative 3) and (2, 0)

Step-by-step explanation:

we have

$y-3=\frac{3}{2}(x-4)$

This is the equation of a line in point slope form

the slope is m=3/2

the point is (4,3)

Remember that

If a ordered pair lie on the given line, then the ordered pair must be satisfy the equation of the line

<u><em>Verify each case</em></u>

1) a line passing through the points (0, negative 3) and (2, 0)

For x=0, y=-3

substitute

$-3-3=\frac{3}{2}(0-4)$

$-6=-6$ ----> is true

The ordered pair (0,-3) lie on the given line

For x=2,y=0

$0-3=\frac{3}{2}(2-4)$

$-3=-3$ ----> is true

The ordered pair (2,0) lie on the given line

therefore

This graph represent the given function

2) a line passing through the points (negative 2, 0) and (0, negative 3)

For x=-2, y=0

substitute

$0-3=\frac{3}{2}(-2-4)$

$-3=-9$ ----> is not true

The ordered pair not lie on the given line

therefore

This graph not represent the given function

3) a line passing through the points (negative 4, negative 3) and (2, 1)

For x=-4, y=-3

substitute

$-3-3=\frac{3}{2}(-4-4)$

$-6=-12$ ----> is not true

The ordered pair not lie on the given line

therefore

This graph not represent the given function

4) a line passing through the points (negative 1, 1) and (1, 1).

For x=-1, y=1

substitute

$1-3=\frac{3}{2}(-1-4)$

$-2=-7.5$ ----> is not true

The ordered pair not lie on the given line

therefore

This graph not represent the given function

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