Vertex = (6, 5)
axis of symmetry is line x = 6
A third point in the parabola is (12, 0)
equation using the vertex is y = -a(x - 6)^2 + 5 = -a(x^2 - 12x + 36) + 5 = -ax^2 + 12ax - 36a + 5
since the parabola passes through point (0, 0)
i.e. -36a + 5 = 0
a = 5/36 = 0.139
Therefore, the equation is y = -0.139x^2 + 12(0.139)x = -0.139x^2 + 1.667x
Y= 12 because anything to the 0 power is 1 so 4*1=4 * 3=12
-7t-3t would be -4t
4 is less than or equal to -4t
Divide 4from -4
-1 is less than or equal to t
Answer:
18\cdot36
Step-by-step explanation:
