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Pavlova-9 [17]
3 years ago
15

What is the value of y in the equation 2(3y + 6 + 3) = 196 − 16?

Mathematics
1 answer:
mafiozo [28]3 years ago
4 0

2(3y + 6 + 3) = 196 - 16

2 x (3y + 9) = 196 - 16

2 x (3y + 9) = 180

2 x 3y + 2 x 9 = 180

6y + 2 x 9 = 180

6y + 18 = 180

6y = 180 - 18

6y = 162

y = 162/6

y = 27




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Answer:

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Step-by-step explanation:

Given,

a=-6

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We have to find out the sum of integers from -6 To 58.

Firstly we will find out the total number of terms that is 'n'.

Here a_1=-6\ and\ a_2=-5

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Now we use the formula of A.P.

T_n=a+(n-1)d

On substituting the values, we get;

58=-6+(n-1)1\\\\n-1=58+6\\\\n-1=64\\\\n=64+1=65

So there are 65 terms in between  -6 To 58.

That means we have to find the sum of 65 terms in between  -6 To 58.

Now we use the formula of Sum of n_terms.

S_n=\frac{n}{2}(2a-(n-1)d)

On substituting the values, we get;

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Hence The Sum Of The Integers From -6 To 58 is <u>1690.</u>

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