If the original side length is "s" and the original slant height is "h", the original surface area is .. S = (base area) +(lateral area) .. S = s² +(1/2)*(4s)*h .. S = s(s +2h)
Now, if we make these replacements: s ⇒ 3s, h ⇒ h/5, we have .. S' = (3s)(3s +2h/5) .. S' = 9s² +(6/5)s*h . . . . . . . the formula for the modified area (in terms of original dimensions)
_____ Of course, in terms of the modified dimensions, the formula is the same: .. S' = s'(s' +2h')
The slopes will be the same but the y-intercept will be different. I graphed out which equation will pass through (4,10) and also be parallel to y=1/2x-8.
